What is the average of 17 over 15?

Ryan wants to use the Fermi process to estimate the number of basketballs that would fill a gymnasium. As part of the process, h

Westkost [7]

A basketball is the shape of a sphere.

The volume of a sphere is given by

$V= \frac{4}{3} \pi r^3$

Given that the diameter of the basketball is 10 in., thus the radius is 10 / 2 = 5 in.

Thus, the volume of the basketball is given by

$V= \frac{4}{3} \pi(5)^3 \\ \\ = \frac{4\times125}{3} \pi=523.6\ in^3$

Therefore, The best approximate of the volume of the basketball is $5\times10^2\ in^3$

3 0

3 years ago

Zoey purchased a new car in 1992 for \$28,000$28,000. The value of the car has been depreciating exponentially at a constant rat

elena-s [515]

400$
Explanation:
In 1992, the price is 28000$ and 9600$ in 1996 so in 4 years the value the car lost is 18400$
Dividing 18400 by 4 years we get 4600 depreciation value per year.
Between 1996 and 1998 there is 2 years
So in 1998 the value of the car will be:
9600 (value in 1996) - 2x4600 = 400$

3 0

3 years ago

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WHATS THE PERIMITER PLS HELP ME

mihalych1998 [28]

I believe the answer is c

4 0

3 years ago

The amount of calories consumed by customers at the Chinese buffet is normally distributed with mean 2885 and standard deviation

aliina [53]

Answer:

a. X~N(2,885, 651)

b. 0.086291

c. 0.00058

d. 3213.10 calories

Step-by-step explanation:

a. -A normal distribution is expressed in the form X~N(mean, standard deviation).

-Let X a random variable denoting the number of calories consumed.

-X is a is a normally distributed random variable with mean 2885 and standard deviation 651.

-This distribution is expressed as X~N(2,885, 651)

b. The probability that less than 2000 calories are consumed is calculated using the formula:

$P(X$

#substitute the given values in the formula to solve for P:

$P(X$

Hence, the probability of consuming less than 2000 calories is 0.08691

c. The proportion of customers consuming more than 5000 calories is calculated as:

$P(X>x)=P(z>\frac{\bar X-\mu}{\sigma})\\\\=P(Z>\frac{5000-2885}{651})\\\\=P(z>3.2488)\\\\=1-0.99942\\\\=0.00058$

Hence, the proportion of customers consuming over 5000 calories is 0.00058

d. The least amount of calories to get the award is calculated as:

1% is equivalent to a z value of 0.50399.

-We equate this to the formula to solve for the mean consumption:

$0.01=P(z>\frac{\bar X-\mu}{\sigma})\\\\=P(z>\frac{\bar X-2885}{651})\\\\\1\%=0.50399 \\\\\frac{\bar X-2885}{651}=0.50399 \\\\\bar X=0.50399\times 651+2885\\\\=3213.09$

Hence, the least amount of calories consumed to qualify for the award is 3213.10 calories.

8 0

4 years ago

What is the answer to 2x - 6 = 8 - x

fenix001 [56]

Move the x's to the same side

2x + x = 8 +6

then simplify

3x = 14

make x stand on its own

(3x)/3 = 14/3

the 3's on the x side cancel

x = 14/3

8 0

3 years ago

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