Answer:
In order for it to benefit his father to buy the pass Seth have to attend the movies for 11 times.
Step-by-step explanation:
Given:
Cost of movie pass = $40
Cost per matinees with pass = $1.00
Cost per matinees without pass = $3.50
To Find:
Number of times must Seth attend in order for it to benefit his father to buy the pass = ?
Solution:
Let x be the number of times he wants to visit
To profit his father
The number of visits without pass = the number of visits with passin the cost of $3.50
Then, without pass if he visits for x times then the cost will be = 3.50x
Also with pass, the number of times he can visit the pass = 
then
x = 11.42
x = 11 (approx)
<h3>
Answer:</h3>
<u>Ratio of perimeters for two pentagons are</u>:
- 32cm²/98cm²
- 16/49 (Divided by 2)
<u>Correct choice</u> - [A] 16:49.
Answer:
The perimeter would also be multiplied by 2.
Step-by-step explanation:
The perimeter would also be multiplied by 2. Suppose the sides of a triangle are 5, 10 and 13. The perimeter would be the sum of the side lengths or 5 + 10 + 13 = 28 ft.
Multiply each side length so 5*2 = 10, 10*2 = 20 and 13*2 = 26. Find the perimeter by finding their sum, 10 + 20 + 26 = 56.
Divide the new perimeter by the old perimeter to find a scale factor.
56/28 = 2.
The new perimeter is exactly 2 times bigger since 2*28 = 56.
Consider expanding the right hand side as
![y=\sqrt[3]{\dfrac{x(x-2)}{x^2+1}}=x^{1/3}(x-2)^{1/3}(x^2+1)^{-1/3}](https://tex.z-dn.net/?f=y%3D%5Csqrt%5B3%5D%7B%5Cdfrac%7Bx%28x-2%29%7D%7Bx%5E2%2B1%7D%7D%3Dx%5E%7B1%2F3%7D%28x-2%29%5E%7B1%2F3%7D%28x%5E2%2B1%29%5E%7B-1%2F3%7D)
Then taking the logarithm of both sides and applying some properties of the logarithm, you have
Now differentiate both sides with respect to 
:
![\dfrac{\mathrm dy}{\mathrm dx}=\dfrac23\dfrac{x^2+x-1}{x(x-2)(x^2+1)}\sqrt[3]{\dfrac{x(x-2)}{x^2+1}}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20dy%7D%7B%5Cmathrm%20dx%7D%3D%5Cdfrac23%5Cdfrac%7Bx%5E2%2Bx-1%7D%7Bx%28x-2%29%28x%5E2%2B1%29%7D%5Csqrt%5B3%5D%7B%5Cdfrac%7Bx%28x-2%29%7D%7Bx%5E2%2B1%7D%7D)
