Ask question

Ask question

All categories

3 years ago

10

Mr.Klein's class is selling candy for a fundraiser. The class has a goal of raising $450 for selling c boxes of candy. Each box

of candy costs $3.75

2 answers:

Bumek [7]3 years ago

4 0

Answer:

The class would need to sell 120 boxes of candy.

Step-by-step explanation:

You divide 450 by 3.75

450 ÷ 3.75 = 120

abruzzese [7]3 years ago

3 0

Answer:

3.75c=450

Step-by-step explanation:

You might be interested in

Suppose you are to select a password of size 4. The first character should be any lowercase letter or a digit, while the second

Goshia [24]

First question seems incomplete :

Answer:

40 ways

Step-by-step explanation:

Question B:

Number of boys = 6

Number of girls = 4

Number of people in committee = 3

Number of ways of selecting committee with atleast 2 girls :

We either have :

(2 girls 1 boy) or (3girls 0 boy)

(4C2 * 6C1) + (4C3 * 6C0)

nCr = n! ÷ (n-r)!r!

4C2 = 4! ÷ 2!2! = 6

6C1 = 6! ÷ 5!1! = 6

4C3 = 4! ÷ 1!3! = 4

6C0 = 6! ÷ 6!0! = 1

(6 * 6) + (4 * 1)

36 + 4

= 40 ways

3 0

3 years ago

출<br> Enter the difference as a mixed number,<br> 10<br> Pls help me

krok68 [10]

Answer: 48/10

Step-by-step explanation: 65/10 - 17/10 = 48/10 also known as 4 8/10

8 0

3 years ago

Read 2 more answers

A simple random sample of size nequals81 is obtained from a population with mu equals 83 and sigma equals 27. (a) Describe the

Ivanshal [37]

Answer:

a) $\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

b) $z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

c) $z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

$P(Z$

d) $z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

$z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2$

$P(-1.2$

Step-by-step explanation:

For this case we know the following propoertis for the random variable X

$\mu = 83, \sigma = 27$

We select a sample size of n = 81

Part a

Since the sample size is large enough we can use the central limit distribution and the distribution for the sampel mean on this case would be:

$\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

Part b

We want this probability:

$P(\bar X>89)$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 89 we got:

$z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

Part c

$P(\bar X$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 75.65 we got:

$z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

$P(Z$

Part d

We want this probability:

$P(79.4 < \bar X < 89.3)$

We find the z scores:

$z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

$z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2$

$P(-1.2$

8 0

3 years ago

Which two complex numbers that could have been added together to make -11+3i

irina [24]

Answer:

Step-by-step explanation:

There are an infinite number of possible solutions.

here's a few

(1 - 4i) + (-12 + 4i)

(-5.5 + 2i) + (-5.5 + i)

(-24 - 27i) + (13 + 30i)

3 0

3 years ago

Which expression is equivalent to -0.55 – 0.47a + a?

Leto [7]

Answer:

-0.55 + 0.53a

Step-by-step explanation:

-0.55 – 0.47a + a

To find an expression equivalent to this, we must simplify the equation to a reasonable extent;

-0.55 – 0.47a + a

= -0.55 + 0.53a

= 0.53a - 0.55

The expression equivalent to the given one is -0.55 + 0.53a or 0.53a - 0.55

8 0

3 years ago