1-s=6-6s help meeeeeee

Find the x and y intercepts and the slope -8x-3y=24

alexandr1967 [171]

First you add 8x on both sides and then you get -3y=8x+24 then you divide -3 on both side and you get y=-8/3x-8 so then the y intercept is 8 and the slope is -8/3. Hope this helped. Please click on the thanks button if this helped. If you have any questions or concerns please ask them down in the comments.

6 0

3 years ago

Find where the function is increasing and decreasing. G(x)=1/x^2 +7

eduard

Inc on (-inf,0)
Dec on (0,inf)

3 0

4 years ago

Evaluate y = 3x, when x = 5<br><br> y = 243<br> y = 125<br> y = 15

Mandarinka [93]

Answer:

C) y=15

Step-by-step explanation:

y=3x

y=3(5)=15

4 0

3 years ago

Newberg City Cafe recently introduced a new flavor of coffee. They served 23 grande cups and 51 jumbo cups of the new coffee tod

yuradex [85]

Answer:

Grand coffee cup = 1469 gm

Jumbo coffee cup = 60 gm

Step-by-step explanation:

Let x be the grande coffee cup and y be the jumbo coffee cup.

Solution:

From the first statement. They served 23 grande cups and 51 jumbo cups of the new coffee today, which equal a total of 36,846 grams.

So, the equation is.

$23x+51y = 36846$ ---------(1)

From the second statement. They served 58 grande cups and 68 jumbo cups of the new coffee tomorrow, which equal a total of 59460 grams.

$58x+68y=59460$ ----------(2)

Solve the equation 1 for x.

$23x = 36846-51y$

$x=\frac{36846}{23}-\frac{51}{23}y$

$x=1602-\frac{51}{23}y$ ---------(3)

Substitute $x=1602-\frac{51}{23}y$ in equation 2.

$58(1602-\frac{51}{23}y)+68y=59460$

$92916-\frac{51\times 58}{23}y+68y=59460$

$-\frac{2958}{23}y+68y=59460-92916$

$\frac{-2958+1564}{23}y=-33456$

$\frac{-1394}{23}y=-33456$

Using cross multiplication.

$y=\frac{-23\times 33456}{-1394}$

$y = 55.99$

y ≅ 60 gram

Substitute y = 60 in equation 3.

$x=1602-\frac{51}{23}\times 60$

$x=1602-\frac{3060}{23}$

$x=1602-133.04$

$x = 1469$ grams

Therefore, grand coffee cup = 1469 gm and jumbo coffee cup = 60 gm

7 0

3 years ago

An assembly consists of two mechanical components. Suppose that the probabilities that the first and second components meet spec

harkovskaia [24]

Answer:

P(X = 0) = 0.0208, P(X = 1) = 0.2484, P(X = 2) = 0.7308

Step-by-step explanation:

Let's define the following events

A: the first component meet specification

B: the second component meet specification

P(A) = 0.87

P(B) = 0.84

Let X be the random variable that represents the number of components in the assembly that meet specifications. Because there are only two mechanical components in the assembly, X can only take the values 0, 1, 2.

P(X = 0) = P(the first component does not meet specification and the second component does not meet specification) =

$P(A^{c}\cap B^{c}) = P(A^{c})P(B^{c})$ (because of independence)

= (0.13)(0.16) = 0.0208

P(X = 1) = P(only one component meet specification) = P[(the first component meet specification and the second component does not meet specification) or (the first component does not meet specification and the second component meet specification)] =

$P[(A\cap B^{c})\cup (A^{c}\cap B)] = P(A\cap B^{c}) + P(A^{c}\cap B)=$ (because sets are mutually exclusive)

$P(A)P(B^{c}) + P(A^{c})P(B)=$ (because of independence)

= (0.87)(0.16) + (0.13)(0.84) = 0.2484

P(X = 2) = P(both components meet specifications) =

$P(A\cap B) = P(A)P(B)$ (because of independence)

= (0.87)(0.84)

= 0.7308

8 0

3 years ago