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2 years ago

Put them in order from the least to greatest. You can use the number line to help!!

Mathematics

1 answer:

choli [55]2 years ago

7 0

Answer: -1, -0.5, -1/10, 0.6

Step-by-step explanation:

-1/10 is the same thing as -0.1.

-0.5 < -0.1 < 0.6

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5) Placido pulls a rope attached to a wagon through a pulley at a rate of q m/s. With dimension as in Figure 5:

Damm [24]

The formula for the speed of the wagon can be found by using Pythagoras theorem, and chain rule of differentiation.

$(a) \ \mathrm{The \ speed \ of \ the \ wagon} , \ \dfrac{dx}{dt} = q -\dfrac{x}{\sqrt{x^2+ 5.76}}$

(b) When x = 0.6 and q = 0.5 m/s, the speed of the wagon is approximately 0.243 m/s.

Reasons:

(a) The distance from the cart to the pulley, r is given by Pythagoras's

theorem as follows;

r = √((3 - 0.6)² + x²) = √(2.4² + x²)

The speed of the wagon = $\mathbf{\dfrac{dx}{dt}}$

The speed of the rope, q = $\mathbf{\dfrac{dr}{dt}}$

By chain rule, we have;

$\dfrac{dr}{dt} = \mathbf{\dfrac{dr}{dx} + \dfrac{dx}{dt}}$

$\dfrac{dr}{dx} = \dfrac{x}{\sqrt{x^2+ 5.76}}$

Therefore;

$\dfrac{dr}{dt} = q =\dfrac{x}{\sqrt{x^2+ 5.76}}+ \dfrac{dx}{dt}$

$\mathrm{The \ speed \ of \ the \ wagon} , \ \dfrac{dx}{dt} = \underline{ q -\dfrac{x}{\sqrt{x^2+ 5.76}}}$

(b) The speed of the wagon when x = 0.6 if q = 0.5 m/s is given as follows;

$\dfrac{dx}{dt} = 0.5 -\dfrac{0.6}{\sqrt{0.6^2+ 5.76}} =\sqrt{\dfrac{1}{17} } \approx 0.243$

The speed of the wagon when x = 0.6 and q = 0.5 m/s, $\dfrac{dx}{dt}$ ≈ 0.243 m/s

Learn more here:

brainly.com/question/17081984

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2 years ago

The science center has 200 people in attendance on Monday. The center expects Saturday's attendance to be 140

Molodets [167]

Answer:

Natasha should have multiplied 140 by 2

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3 years ago

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(8x^2-6x-2)-(4x^2+6)

Anestetic [448]

The answer is 32x^4-24x^3+40x^2-36x-12

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3 years ago

Brainliest and show work on how to do all 3

ddd [48]

Answer:

Question 1: 34.56 mm

Question 2: 12.57 in

Question 3: 15.70 yd

Step-by-step explanation:

3 0

1 year ago

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Write 140 as the product of its prime factors.

Romashka-Z-Leto [24]

$140:\bold{2}=70\\\\70:\bold{2}=35\\\\35:\bold{5}=7\\\\7:\bold{7}=\underline{1}$

so:

$140=2\cdot2\cdot5\cdot7=\boxed{2^2\cdot5\cdot7}$

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2 years ago

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