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Arisa [49]
3 years ago
14

Determine the radius of the cone, if the volume of the cone is 125 cm and

Mathematics
1 answer:
disa [49]3 years ago
7 0

Answer: 3.15

Step-by-step explanation:

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Ldentify the following sections of the textbook.
Tema [17]
I don’t know what the drop down options are so I can’t answer your question. Sorry but can u pls help answer my question I just posted? That would be very helpful thx!
7 0
3 years ago
Find the distance and midpoint for the following coordinates.<br> P(7.6 , 10.1) and Q(4.6 , 3.1)
KATRIN_1 [288]
Solving for the midpoint:

x - coordinate: (7.6 + 4.6)/2 = 6.1
y - coordinate: (10.1 + 3.1)/2 = 6.6

Midpoint: (6.1 , 6.6)

Solving for the distance:

Distance formula: sqrt( (x2 - x1)^2 + (y2 - y1)^2 )

D = sqrt( (7.6 - 4.6)^2 + (10.1 - 3.1)^2 <span>)
D = sqrt( 3^2 + 7^2)
D = sqrt(58)
D = 7.62 units

Distance = 7.62 units</span>
8 0
3 years ago
The base of a rectangular fish tank measures 18 inches long by 10 inches wide. If it is filled with 1,080 cubic
Oxana [17]

Answer:

Volume = length x width x height

V = 18 x 8 x 12 = 1728 cm3 = 1728 ml = 1.729 liters

Step-by-step explanation:

5 0
3 years ago
Write and equation of the translated or rotated graph in general form (picture below)
WINSTONCH [101]

Answer:

The answer is hyperbola; (x')² - (y')² - 16 = 0 ⇒ answer (a)

Step-by-step explanation:

* At first lets talk about the general form of the conic equation

- Ax² + Bxy + Cy²  + Dx + Ey + F = 0

∵ B² - 4AC < 0 , if a conic exists, it will be either a circle or an ellipse.

∵ B² - 4AC = 0 , if a conic exists, it will be a parabola.

∵ B² - 4AC > 0 , if a conic exists, it will be a hyperbola.

* Now we will study our equation:

 xy = -8

∵ A = 0 , B = 1 , C = 0

∴ B² - 4 AC = (1)² - 4(0)(0) = 1 > 0

∴ B² - 4AC > 0

∴ The graph is hyperbola

* The equation xy = -8

∵ We have term xy that means we rotated the graph about

  the origin by angle Ф

∵ Ф = π/4

∴ We rotated the x-axis and the y-axis by angle π/4

* That means the point (x' , y') it was point (x , y)

- Where x' = xcosФ - ysinФ and y' = xsinФ + ycosФ

∴ x' = xcos(π/4) - ysin(π/4) , y' = xsin(π/4) + ycos(π/4)

∴ x' = x/√2 - y/√2 = (x - y)/√2

∴ y' = x/√2 + y/√2 = (x + y)/√2

* Lets substitute x' and y' in the 1st answer

∵ (x')² - (y')² - 16 = 0

∴ (\frac{x-y}{\sqrt{2}})^{2}-(\frac{x+y}{\sqrt{2}})^{2}=

 ( \frac{x^{2}-2xy+y^{2}}{2})-(\frac{x^{2}+2xy+y^{2}}{2})-16=0

* Lets open the bracket

∴ \frac{x^{2}-2xy+y^{2}-x^{2}-2xy-y^{2}}{2}-16=0

* Lets add the like terms

∴ \frac{-4xy}{2}-16=0

* Simplify the fraction

∴ -2xy - 16 = 0

* Divide the equation by -2

∴ xy + 8 = 0

∴ xy = -8 ⇒ our equation

∴ Answer (a) is our answer

∴ The answer is hyperbola; (x')² - (y')² - 16 = 0

* Look at the graph:

- The black is the equation (x')² - (y')² - 16 = 0

- The purple is the equation xy = -8

- The red line is x'

- The blue line is y'

6 0
3 years ago
Read 2 more answers
Which statements is an example of the symmetric property of congruence?
jok3333 [9.3K]

Answer:

I believe the answer is C.

Step-by-step explanation:

Example:

For any angles A and B , if ∠ A ≅ ∠ B , then ∠ B ≅ ∠ A . Order of congruence does not matter.

8 0
2 years ago
Read 2 more answers
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