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3 years ago

7

Warm fronts and stationary fronts bring? (A) severely bad weather (B) clear skies (C) light precipitation (D) mid-latitude cyclo

nes

1 answer:

wariber [46]3 years ago

4 0

Answer:

C

Step-by-step explanation:

You might be interested in

An article suggests that a poisson process can be used to represent the occurrence of structural loads over time. suppose the me

kirill115 [55]

Answer:

a) $\lambda_1 = 2*2 = 4$

And let X our random variable who represent the "occurrence of structural loads over time" we know that:

$X(2) \sim Poi (4)$

And the expected value is $E(X) = \lambda =4$

So we expect 4 number of loads in the 2 year period.

b) $P(X(2) >6) = 1-P(X(2)\leq 6)= 1-[P(X(2) =0)+P(X(2) =1)+P(X(2) =2)+...+P(X(2) =6)]$

$P(X(2) >6) = 1- [e^{-4}+ \frac{e^{-4}4^1}{1!}+ \frac{e^{-4}4^2}{2!} +\frac{e^{-4}4^3}{3!} +\frac{e^{-4}4^4}{4!}+\frac{e^{-4}4^5}{5!}+\frac{e^{-4}4^6}{6!}]$

And we got: $P(X(2) >6) =1-0.889=0.111$

c) $e^{-2t} \leq 2$

We can apply natural log in both sides and we got:

$-2t \leq ln(0.2)$

If we multiply by -1 both sides of the inequality we have:

$2t \geq -ln(0.2)$

And if we divide both sides by 2 we got:

$t \geq \frac{-ln(0.2)}{2}$

$t \geq 0.8047$

And then we can conclude that the time period with any load would be 0.8047 years.

Step-by-step explanation:

Previous concepts

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:

$P(X=x)=\lambda e^{-\lambda x}$

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution"

Solution to the problem

Let X our random variable who represent the "occurrence of structural loads over time"

For this case we have the value for the mean given $\mu = 0.5$ and we can solve for the parameter $\lambda$ like this:

$\frac{1}{\lambda} = 0.5$

$\lambda =2$

So then $X(t) \sim Poi (\lambda t)$

X follows a Poisson process

Part a

For this case since we are interested in the number of loads in a 2 year period the new rate would be given by:

$\lambda_1 = 2*2 = 4$

And let X our random variable who represent the "occurrence of structural loads over time" we know that:

$X(2) \sim Poi (4)$

And the expected value is $E(X) = \lambda =4$

So we expect 4 number of loads in the 2 year period.

Part b

For this case we want the following probability:

$P(X(2) >6)$

And we can use the complement rule like this

$P(X(2) >6) = 1-P(X(2)\leq 6)= 1-[P(X(2) =0)+P(X(2) =1)+P(X(2) =2)+...+P(X(2) =6)]$

And we can solve this like this using the masss function:

$P(X(2) >6) = 1- [e^{-4}+ \frac{e^{-4}4^1}{1!}+ \frac{e^{-4}4^2}{2!} +\frac{e^{-4}4^3}{3!} +\frac{e^{-4}4^4}{4!}+\frac{e^{-4}4^5}{5!}+\frac{e^{-4}4^6}{6!}]$

And we got: $P(X(2) >6) =1-0.889=0.111$

Part c

For this case we know that the arrival time follows an exponential distribution and let T the random variable:

$T \sim Exp(\lambda=2)$

The probability of no arrival during a period of duration t is given by:

$f(T) = e^{-\lambda t}$

And we want to find a value of t who satisfy this:

$e^{-2t} \leq 2$

We can apply natural log in both sides and we got:

$-2t \leq ln(0.2)$

If we multiply by -1 both sides of the inequality we have:

$2t \geq -ln(0.2)$

And if we divide both sides by 2 we got:

$t \geq \frac{-ln(0.2)}{2}$

$t \geq 0.8047$

And then we can conclude that the time period with any load would be 0.8047 years.

3 0

3 years ago

dans ice cream comes in to cartons sizes. the large carton is 4 1/2 pounds the small carton holds 1 3/4 pounds les. how much ice

sineoko [7]

So you make them into an improper fraction with a common denominator. so it would be 18/4 - 7/4, and it equals 11/4, or 2 & 3/4!

6 0

3 years ago

Three different fraction equivalent 1

olga nikolaevna [1]

Answer:

3/3, 9/9, 12/12

Step-by-step explanation:

Equivilant fractions are only the ssame number on top of each other OR a number on top of a 1

7 0

3 years ago

Plsssssss answerrrrrr

MaRussiya [10]

Answer:

Step-by-step explanation:

Angle C and angle with 120 degrees measure are alternate and their measurement is equal so C = 120

angle C and angle B are supplementary and so their sum is equal to 180

B = 180 - 120

B = 60

angle D and angle B are also alternate so their measure is also equal to each other therefore

D = 60

7 0

3 years ago

Simplify (4x^2+2)÷(2x^2-9x-5)

frosja888 [35]

Answer:

4.1 Pull out like factors :

4x2 + 2 = 2 • (2x2 + 1)

Polynomial Roots Calculator :

4.2 Find roots (zeroes) of : F(x) = 2x2 + 1

Polynomial Roots Calculator is a set of methods aimed at finding values of x for which F(x)=0

Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers x which can be expressed as the quotient of two integers The Rational Root Theorem states that if a polynomial zeroes for a rational number P/Q then P is a factor of the Trailing Constant and Q is a factor of the Leading Coefficient

In this case, the Leading Coefficient is 2 and the Trailing Constant is 1.

The factor(s) are:

of the Leading Coefficient : 1,2

of the Trailing Constant : 1

Let us test ....

P Q P/Q F(P/Q) Divisor -1 1 -1.00 3.00 -1 2 -0.50 1.50 1 1 1.00 3.00 1 2 0.50 1.50

Polynomial Roots Calculator found no rational roots

Trying to factor by splitting the middle term

4.3 Factoring 2x2 - 9x - 5

The first term is, 2x2 its coefficient is 2 .

The middle term is, -9x its coefficient is -9 .

The last term, "the constant", is -5

Step-1 : Multiply the coefficient of the first term by the constant 2 • -5 = -10

Step-2 : Find two factors of -10 whose sum equals the coefficient of the middle term, which is -9 .

-10 + 1 = -9 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -10 and 1

2x2 - 10x + 1x - 5

Step-4 : Add up the first 2 terms, pulling out like factors :

2x • (x-5)

Add up the last 2 terms, pulling out common factors :

1 • (x-5)

Step-5 : Add up the four terms of step 4 :

(2x+1) • (x-5)

Which is the desired factorization

Final result :

2 • (2x2 + 1) —————————————————— (x - 5) • (2x + 1)

5 0

2 years ago