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3 years ago

What is an explicit rule in math?

Mathematics

2 answers:

timofeeve [1]3 years ago

4 0

Answer:

An explicit formula designates the nth term of the sequence, as an expression of n (where n = the term's location). It defines the sequence as a formula in terms of n. ... This example is an arithmetic sequence(the same number, 5, is added to each term to get to the next term).

Step-by-step explanation:

Oxana [17]3 years ago

3 0

Answer:

An explicit formula designates the nth term of the sequence, as an expression of n (where n = the term's location). It defines the sequence as a formula in terms of n. It may be written in either subscript notation a n, or in functional notation, f (n). Sequence: {10, 15, 20, 25, 30, 35, ...}.

Step-by-step explanation:

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Sophie practices the piano 105 minutes in 1 week. If t represents the total time she practices for any number of days, d, write

Alex Ar [27]

Answer:

Step-by-step explanation:

You must first know that 1 week = 7days

If Sophie practices the piano 105 minutes in 1 week, this can be expressed as;

105 minutes = 7days

to calculate the total time t that she practices for any number of days, d, we will say;

t minutes = d days.

Solving both expression;

105 minutes = 7days

t minutes = d days.

Cross multiply;

7 * t = 105 * d

7t = 105d

Divide both sides by 7;

7t/7 = 105d/7

t = 15d

Hence a proportional equation for t in terms of d that matches the context is expressed as t = 15d

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3 years ago

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2 years ago

A set of equations is given below:

miv72 [106K]

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3 years ago

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iren2701 [21]

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2 years ago

A hyperbola centered at the origin has verticies at (add or subtract square root of 61,0 and foci at (add or subtract square roo

deff fn [24]

Answer:

$\frac{x^2}{61}-\frac{y^2}{37} =1$

Step-by-step explanation:

The standard equation of a hyperbola is given by:

$\frac{(x-h)^2}{a^2} -\frac{(y-k)^2}{b^2} =1$

where (h, k) is the center, the vertex is at (h ± a, k), the foci is at (h ± c, k) and c² = a² + b²

Since the hyperbola is centered at the origin, hence (h, k) = (0, 0)

The vertices is (h ± a, k) = (±√61, 0). Therefore a = √61

The foci is (h ± c, k) = (±√98, 0). Therefore c = √98

Hence:

c² = a² + b²

(√98)² = (√61)² + b²

98 = 61 + b²

b² = 37

b = √37

Hence the equation of the hyperbola is:

$\frac{x^2}{61}-\frac{y^2}{37} =1$

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3 years ago