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Doss [256]
3 years ago
10

1.) x - 4y = 11

Mathematics
1 answer:
storchak [24]3 years ago
4 0
Y= -5
X= -9

Showing work is a pain......
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Prove the identity.<br> cosh(−x) = cosh(x)
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346772.99378 x 222222666886=
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7.706081948 lowecase10uppercase16

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7 0
2 years ago
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P^7n^3/p^4n^2 simplified <br> a.p^3n <br> b.p^11n^5 <br> c.(1/p^3n) <br> d.(1/p^11n^5)
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5 0
3 years ago
A production process is checked periodically by a quality control inspector. the inspector selects simple random samples of 30 f
777dan777 [17]

Answer:

Population Mean = 2.0

Population Standard deviation = 0.03

Step-by-step explanation:

We are given that the inspector selects simple random samples of 30 finished products and computes the sample mean product weight.

Also, test results over a long period of time show that 5% of the values are over 2.1 pounds and 5% are under 1.9 pounds.

Now, mean of the population is given the average of two extreme boundaries because mean lies exactly in the middle of the distribution.

So,   Mean, \mu = \frac{1.9+2.1}{2} = 2.0

Therefore, mean for the population of products produced with this process is 2.

Since, we are given that 5% of the values are under 1.9 pounds so we will calculate the z score value corresponding to a probability of 5% i.e.

             z = -1.6449 {from z % table}

We know that z formula is given by ;  

                Z = \frac{Xbar - \mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

              -1.6449 = \frac{1.9 - 2.0}{\frac{\sigma}{\sqrt{n} } }     ⇒  \frac{\sigma}{\sqrt{n} }  = \frac{-0.1}{-1.6449}  

                                           ⇒ \sigma = 0.0608 * \sqrt{30}  {as sample size is given 30}

                                           ⇒ \sigma = 0.03 .

Therefore, Standard deviation for the population of products produced with this process is 0.0333.

7 0
3 years ago
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