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Setler [38]
3 years ago
15

PLEASE HELP!! Image Attached! find the value of y, rounded to the nearest tenth

Mathematics
2 answers:
Sunny_sXe [5.5K]3 years ago
7 0

Answer: y is equal to 3.89,

Step-by-step explanation: This question can be solved using the theorem of the power of a point.

The power of a point Theorem states that if a two lines intercept at a point that is intersect with the center of the circle, the lines will create either one segment (S) or two segments (s1 and s2). And the multiplication of each segment equal, which is s1s2 for line one is equal to s1s2 for line two.

Therefore for the diagram.

Using the power of a point Theorem;

9 ×y = 5 × 7

9y = 35

Therefore;

y = 35 ÷ 9 = 3.88889

y = 3.89

m_a_m_a [10]3 years ago
5 0
5 * 7 = 9y
35 = 9y
<span> <span> <span> 3.8888888889 </span> </span> </span>
y = 3.9

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4 years ago
The ammunition storage room has 10 feet between the floor and the ceiling. Each box of ammunition is 10 feet tall. Each crate of
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Answer:

the maximum number of crates that can be stacked between the floor and ceiling

\frac{height \hspace{0.1cm} of  \hspace{0.1cm} ammunition \hspace{0.1cm} box}{height \hspace{0.1cm} of  \hspace{0.1cm} each \hspace{0.1cm} crate}  = \frac{10 \hspace{0.1cm}  feet}{12 \hspace{0.1cm}  inches}  =  \frac{10 \times 12  \hspace{0.1cm} inches }{12  \hspace{0.1cm} inches}  = 10 \hspace{0.1cm}  crates

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Step-by-step explanation:

i) the maximum number of crates that can be stacked between the floor and ceiling

\frac{height \hspace{0.1cm} of  \hspace{0.1cm} ammunition \hspace{0.1cm} box}{height \hspace{0.1cm} of  \hspace{0.1cm} each \hspace{0.1cm} crate}  = \frac{10 \hspace{0.1cm}  feet}{12 \hspace{0.1cm}  inches}  =  \frac{10 \times 12  \hspace{0.1cm} inches }{12  \hspace{0.1cm} inches}  = 10 \hspace{0.1cm}  crates

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