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sukhopar [10]
3 years ago
13

What’s least to greatest 3/5 2/4 1/3

Mathematics
2 answers:
lakkis [162]3 years ago
5 0

ANSWER

LEAST TO GREATEST 3/5, 2/4,1/3

Oxana [17]3 years ago
4 0

Answer:

Step-by-step explanation:

Converting to decimal

3/5 = 0.6

2/4 = 0.5

1/3 = 0.3

Least to greatest = 1/3, 2/4, 3/5

You might be interested in
7-0.3×&gt;4<br>solve for x​
Troyanec [42]

Answer:

x<10

Step-by-step explanation:

Add '-7' to each side of the equation.

7 + -7 + -0.3x = 4 + -7

Combine like terms: 7 + -7 = 0

0 + -0.3x = 4 + -7

-0.3x = 4 + -7

Combine like terms: 4 + -7 = -3

-0.3x = -3

Divide each side by '-0.3'.

x = 10

Simplifying

x = 10

4 0
3 years ago
Liliana is making a vase with a circular base. She wants the area of the base to be between 135 cm2 and 155 cm2. Which circle co
Umnica [9.8K]

Answer:

(b) Circle C is shown. Line segment A C is a radius with length 7 centimeters.

Step-by-step explanation:

Given

Minimum\ Area = 135cm^2

Maximum\ Area = 155cm^2

\pi = 3.14

Required

Which circle could she use

To do this, we simply calculate the areas of all the given circles

The area of a circle is:

Area = \pi r^2

Where

r = radius

a.\ r = 6cm

The area is calculated as thus:

Area = \pi r^2

Area = 3.14 * (6cm)^2

Area = 3.14 * 36cm^2

Area = 114.04cm^2

b.\ r = 7cm

The area is calculated as thus:

Area = \pi r^2

Area = 3.14 * (7cm)^2

Area = 3.14 * 49cm^2

Area = 153.86cm^2

<em></em>

c.\ r = 8cm

The area is calculated as thus:

Area = \pi r^2

Area = 3.14 * (8cm)^2

Area = 3.14 * 64cm^2

Area = 200.96cm^2

d.\ r = 9cm

The area is calculated as thus:

Area = \pi r^2

Area = 3.14 * (9cm)^2

Area = 3.14 * 81cm^2

Area = 254.34cm^2

<em>From the calculations above; only the circle in option (b) has an area within the required range of 135 to 155cm^2</em>

6 0
2 years ago
Read 2 more answers
A rain gutter is made from sheets of aluminum that are 16 inches wide by turning up the edges to form right angles. Determine th
blsea [12.9K]

Answer:

Depth of the rain gutter is 8 inches

Step-by-step explanation:

Let’s assume ‘x’ is the depth of the rain gutter

Then the width of the rain gutter can be written as 16 - 2x

Cross sectional area

A = depth x width

Substitute values

A = x*(16 - 2x)

A = 16x – 2x^2

Now according to axis of symmetry for maximum area x = -b/2a

x = -16/2*(-2)

x = 4 inches depth of rain gutter, substitute the value of x to get

Width of rain gutter 16 – 2(4) = 8 inches

Area of the rain gutter for maximum water flow

A = 4 * 8

A = 32 square inch.

8 0
3 years ago
HELP PLEASE!!!!!! Find the speed of an athlete who makes 4and3/4 laps in 3mins45 seconds on a 400m field in m/s​
Rom4ik [11]

Given:

An athlete who makes 4\dfrac{3}{4} laps in 3 mins 45 seconds on a 400m field.

To find:

The speed of the athlete in m/s.

Solution:

We know that,

Distance covered in 1 lap = 400 m

Distance covered in 4\dfrac{3}{4} laps = 4\dfrac{3}{4}\times 400 m

                                               = \dfrac{19}{4}\times 400 m

                                               = 1900 m

We know that,

1 minute = 60 seconds

3 minutes = 180 seconds

3 minutes 45 second = 180 + 45 seconds

                                   = 225 second

The speed of the athlete is:

Speed=\dfrac{Distance}{Time}

Speed=\dfrac{1900}{225}

Speed\approx 8.44

Therefore, the speed of the athlete is about 8.44 m/s.

7 0
2 years ago
Trigonometry <br> Find x<br> 8.3 <br> 34 degrees
Diano4ka-milaya [45]

Answer:

Step-by-step explanation:

In Triangle

A

B

C

with the right angle at

C

, let

a

,

b

, and

c

be the opposite, the adjacent, and the hypotenuse of

∠

A

. Then, we have

sin

A

=

a

c

⇒

m

∠

A

=

sin

−

1

(

a

c

)

sin

B

=

b

c

⇒

m

∠

B

=

sin

−

1

(

b

c

)

I hope that this was helpful.

Wataru ·  1 · Oct 29 2014

How do you find all the missing angles, if you know one of the acute angles of a right triangle?

The sum of the measures of all the angles in a triangle is always equal to

180

o

.

In a right triangle, however, one of the angles is already known: the right angle, or the

90

o

angle.

Let the other two angles be

x

and

y

(which will be acute).

Applying these conditions, we can say that,

x

+

y

+

90

o

=

180

o

x

+

y

=

180

o

−

90

o

x

+

y

=

90

o

That is, the sum of the two acute angles in a right triangle is equal to

90

o

.

If we know one of these angles, we can easily substitute that value and find the missing one.

For example, if one of the angles in a right triangle is

25

o

, the other acute angle is given by:

25

o

+

y

=

90

o

y

=

90

o

−

25

o

y

=

65

o

Tanish J. ·  1 · Nov 26 2014

How do you know what trigonometric function to use to solve right triangles?

Right triangles are a special case of triangles. You always know at least one angle, the right angle, and depending on what else you know, you can solve the rest of the triangle with fairly simple formulas.

http://etc.usf.edu/clipart/36500/36521/tri11_36521.htm

If you know any one side and one angle, or any two sides, you can use the pneumonic soh-cah-toa to remember which trig function to use to solve for others.

s

−

i

n

(

θ

)

=

 

o

−

pposite

/

 

h

−

ypotenuse

c

−

o

s

(

θ

)

=

a

−

djacent

/

h

−

ypotenuse

t

−

a

n

(

θ

)

=

o

−

pposite

/

a

−

djacent

Opposite refers to the side which is not part of the angle, adjacent refers to the side that is part of the angle, and the hypotenuse is the side opposite the right angle, which is

C

in the image above.

For example,lets say you know the length of

a

and the value of angle

A

in the above triangle. Using the cosine function you can solve for

c

, the hypotenuse.

cos

(

A

)

=

a

c

Which rearranges to;

c

=

a

cos

(

A

)

If you know the length of both sides

a

and

b

, you can solve for the tangent of either angle

A

or

B

.

tan

(

A

)

=

a

b

Then you take the inverse tangent,

tan

−

1

to find the value of

A

.

Zack M. ·  4 · Dec 7 2014

What are inverse trigonometric functions and when do you use it?

Inverse trigonometric functions are useful in finding angles.

Example

If

cos

θ

=

1

√

2

, then find the angle

θ

.

By taking the inverse cosine of both sides of the equation,

⇒

cos

−

1

(

cos

θ

)

=

cos

−

1

(

1

√

2

)

since cosine and its inverse cancel out each other,

⇒

θ

=

cos

−

1

(

1

√

2

)

=

π

4

I hope that this was helpful.

Wataru ·  1 · Nov 2 2014

What is Solving Right Triangles?

Solving a right triangle means finding missing measures of sides and angles from given measures of sides and angles.

I hope that this was helpful.

Wataru ·  3 · Nov 6 2014

5 0
2 years ago
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