2 years ago

What is the equation of a circle with a center (-9,2) and radius 5?

1 answer:

4 0

Answer:

(x+9)^2 + ( y-2) ^2 = 25

Step-by-step explanation:

The equation of a circle can be written as

(x-h)^2 + ( y-k) ^2 = r^2 where ( h,k) is the center and r is the radius

(x--9)^2 + ( y-2) ^2 = 5^2

(x+9)^2 + ( y-2) ^2 = 25

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Lelu [443]

Answer:

$\frac{n^{2}}{2a}$

Step-by-step explanation:

Just split it up first $\frac{9an^{3}}{18a^{2}n}=\frac{9}{18}\times \frac{a}{a^2} \times\frac{n^3}{n}$
Then 9 divided by 18 can be simplified into the fraction 1/2
What can go into $a$ and $a^2$ ? a itself right, so if you divide a by a you get 1, if you divide $a^2$ by a you get a
Same as the a fraction, if you divide $n^3$ by n you get $n^2$
$\frac{9an^{3}}{18a^{2}n}=\frac{9}{18}\times \frac{a}{a^2} \times\frac{n^3}{n}=\frac{1}{2}\times \frac{1}{a} \times\frac{n^2}{1}=\frac{n^{2}}{2a}$