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erik [133]
3 years ago
12

Suppose that there are two types of tickets to a show: advance and same-day. Advance tickets cost 40

Mathematics
2 answers:
Sholpan [36]3 years ago
8 0
There were 40 advance tickets sold, and 30 same-day tickets sold.
Fudgin [204]3 years ago
6 0
55 advanced tickets
2 same-day tickets
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What is the value of the discriminant in the equation shown below? x^2-4x+10=0?
Assoli18 [71]
I think the discriminant would be -24
5 0
3 years ago
Suppose astronomers built a 50-meter telescope. how much greater would its light-collecting area be than that of the 10-meter ke
drek231 [11]

Answer: Its light-collecting area would be 25 times greater than that of the 10-meter keck telescope.

Step-by-step explanation:

1. To solve this problem you must apply the formula for calculate the area of a circle, which is shown below:

A=r^{2}\pi

Where<em> r</em> is the radius of the circle.

2. The diameter of a circle is:

D=\frac{r}{2}

Where <em>r</em> is the radius of the circle.

3. Therefore, keeping this on mind, you have that the light-collecting area of a  50-meter keck telescope is:

A_1=(\frac{50m}{2})^{2}\pi=1963,49m^{2}

4. And the light-collecting area of a 10-meter keck telescope is:

A_2=(\frac{10m}{2})^{2}\pi=78.53m^{2}

5. Divide A_1 by A_2, then:

\frac{1963.49m^{2}}{78.53m^{2}}=25

6. Therefore, its light-collecting area would be 25 times greater than that of the 10-meter keck telescope.

4 0
4 years ago
Describe how to write 3,482,000,000 in scientific notation.
devlian [24]
It needs to be a number multiplicated by 10 with a round power. With your number, s
you should write it like that : 3.482000000x10^9 (if your zeros are significant, otherwise 3.482x10^9) OR 3.482000000G (for Giga=1×10^9)
6 0
4 years ago
In parallelogram DEFG, DH = x + 1, HF = 3y, G H = 3 x − 4 , and HE = 5y + 1. Find the values of x and y. The diagram is not draw
Nana76 [90]

Answer:

see explanation

Step-by-step explanation:

Using the property of parallelograms

• The diagonals bisect each other, hence

DH = HF and GH = HE

x + 1 = 3y and 3x - 4 = 5y + 1 ⇒ 3x = 5y + 5

Solving the 2 equations simultaneously

x + 1 = 3y → (1)

3x = 5y + 5 → (2)

rearrange (1) expressing x in terms of y

x = 3y - 1 → (3)

substitute x = 3y - 1 in (2)

3(3y - 1) = 5y + 5

9y - 3 = 5y + 5 ( subtract 5y from both sides )

4y - 3 = 5 ( add 3 to both sides )

4y = 8 ( divide both sides by 4 )

y = 2

substitute y = 2 into (3)

x = (3 × 2) - 1 = 6 - 1 = 5

Hence x = 5, y = 2



3 0
3 years ago
Kelly is 3 years younger than her sister. The sum of their ages is 34 years. How old is Kelly and how old is her sister? AN EQUA
KiRa [710]
Kelly's sister is x years old.
Kelly is 3 years younger than her sister, so Kelly is x - 3 years old.
The sum of their ages is x + x - 3 = 2x - 3.
The sum of their ages is 34, so

2x - 3 = 34

2x = 37

x = 18.5 Kelly's sister's age.

x - 3 = 18.5 - 3 = 15.5 Kelly's age.

Kelly's sister is 18.5 years old.
Kelly is 15.5 years old.
5 0
3 years ago
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