Question

Find the equation of the line perpendicular to the line x=9 that passes through the point (9,-1)

Answer 1

Answer:

y =1

Step-by-step explanation:

$(9,-1)=(x ,y)\\\\x =m_1 =9\\m_2 = \frac{-1}{m_1} = \frac{-1}{9} = -\frac{1}{9} \\\\Substitute \:the \:values\:into ;\\y =mx+b\\\\-1 =-\frac{1}{9} (9) +b\\-1 = -1+b\\-1+1 = b\\0 =b\\m= 1 \\Substitute\:the\:new\:values\:into ;\\y = mx+b\\y = 1 x +0\\ y= 1$

Answer 2

Answer:

y = -1

Step-by-step explanation:

Notice that the line x = 9 is a vertical line, therefore a line perpendicular to it will be a horizontal line of the form y = constant number.

Since we want it to go through the point (9, -1), then we know that that y value needs to be "-1", and the equation of the line will be given by the expression:

y = -1