Answer:
The answer is A.-2, |-4/5|, |-1|, |3.5|, |-4.2|
Step-by-step explanation:
<span>A
and B must be invertible, we have UA=B, since A is invertible. A^-1 exists, by multiplying with A^-1,
we have UA A^-1 =B A^-1. But AA^-1 = I (identity matrix)
and XI=X, for all matrix X, we find UI= B A^-1, and U= B A^-1.</span>
Answer:
Step-by-step explain
Find the horizontal asymptote for f(x)=(3x^2-1)/(2x-1) :
A rational function will have a horizontal asymptote of y=0 if the degree of the numerator is less than the degree of the denominator. It will have a horizontal asymptote of y=a_n/b_n if the degree of the numerator is the same as the degree of the denominator (where a_n,b_n are the leading coefficients of the numerator and denominator respectively when both are in standard form.)
If a rational function has a numerator of greater degree than the denominator, there will be no horizontal asymptote. However, if the degrees are 1 apart, there will be an oblique (slant) asymptote.
For the given function, there is no horizontal asymptote.
We can find the slant asymptote by using long division:
(3x^2-1)/(2x-1)=(2x-1)(3/2x+3/4-(1/4)/(2x-1))
The slant asymptote is y=3/2x+3/4
C is 2020 bdecuase I want points
Answer:
Step-by-step explanation:
