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3 years ago

What type of triangle has side lengths 4, 4 squared 15, and 16?

Mathematics

1 answer:

zloy xaker [14]3 years ago

7 0

Answer:

acute triangle

because you have 2 tall sides and 1 short

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A machine covers 5/8 square foot in 1/4 hour

VLD [36.1K]

The question is incomplete. Here is the complete question:

A machine covers 5/8 square foot in 1/4 hour. what is the unit rate?

Answer:

2.5 square feet per hour

Step-by-step explanation:

Given:

Area covered by a machine = $frac{5}{8}\ ft^2$

Time taken to cover the given area = $\frac{1}{4}\ h$

Now, unit rate of the first quantity with respect to second quantity is the magnitude of the first quantity being when the second quantity is one unit.

Here, the first quantity is the area covered and the second quantity is the time taken.

So, unit rate is the area covered by the machine in 1 hour.

In order to find that, we use the unitary method and divide the area by the total time taken. Therefore,

$Unit\ rate=\frac{Total\ area\ covered}{Total\ time\ taken}\\\\Unit\ rate=(\frac{5}{8}\ ft^2)\div (\frac{1}{4}\ h)\\\\Unit\ rate=\frac{5}{8}\times \frac{4}{1}\ ft^2/h\\\\Unit\ rate=\frac{20}{8}=2.5\ ft^2/h$

Thus, the unit rate is 2.5 square feet per hour.

5 0

3 years ago

What is the solution for x in the equation?<br> 9x - 20 - 4x = 40

yan [13]

Answer:

Step-by-step explanation:

X=12

4 0

3 years ago

Read 2 more answers

Can someone help??plzzz..

Sav [38]

When you are multiplying 2 numbers with exponents, you need to add the exponent. When you multiply an exponent with an exponent, you multiply them.

So,
(3^2 x 7^4) ^9
First multiply the base and add exponents = ( 21^6) ^9
= 21 ^6x9
21^54
The same rule applies for variables, just pretend there is an imaginary 1.

4 0

4 years ago

Help ? If anyone knows a answer key or something that’ll help me, I’ll really appreciate it.

OLEGan [10]

Answer:

no i dont onoq what will you do

4 0

4 years ago

Suppose that only 20% of all drivers come to a complete stop at an intersection having flashing red lights in all directions whe

Lina20 [59]

Answer:

a) 91.33% probability that at most 6 will come to a complete stop

b) 10.91% probability that exactly 6 will come to a complete stop.

c) 19.58% probability that at least 6 will come to a complete stop

d) 4 of the next 20 drivers do you expect to come to a complete stop

Step-by-step explanation:

For each driver, there are only two possible outcomes. Either they will come to a complete stop, or they will not. The probability of a driver coming to a complete stop is independent of other drivers. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

20% of all drivers come to a complete stop at an intersection having flashing red lights in all directions when no other cars are visible.

This means that $p = 0.2$

20 drivers

This means that $n = 20$

a. at most 6 will come to a complete stop?

$P(X \leq 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{20,0}.(0.2)^{0}.(0.8)^{20} = 0.0115$

$P(X = 1) = C_{20,1}.(0.2)^{1}.(0.8)^{19} = 0.0576$

$P(X = 2) = C_{20,2}.(0.2)^{2}.(0.8)^{18} = 0.1369$

$P(X = 3) = C_{20,3}.(0.2)^{3}.(0.8)^{17} = 0.2054$

$P(X = 4) = C_{20,4}.(0.2)^{4}.(0.8)^{16} = 0.2182$

$P(X = 5) = C_{20,5}.(0.2)^{5}.(0.8)^{15} = 0.1746$

$P(X = 6) = C_{20,6}.(0.2)^{6}.(0.8)^{14} = 0.1091$

$P(X \leq 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) = 0.0115 + 0.0576 + 0.1369 + 0.2054 + 0.2182 + 0.1746 + 0.1091 = 0.9133$