Which table contains the vertex of the graph represented by y=x^2-6x+4?
1 answer:
vertex = (3,- 5 )
given a quadratic in standard form : y = ax² + bx + c ( a ≠ 0 ), then
the x-coordinate of the vertex is
= -
y = x² - 6x + 4 is in standard form
with a = 1, b = - 6 and c = 4, hence
= -
= 3
substitute this value into the equation for y- coordinate
y = 3² - 6(3) + 4 = 9 - 18 + 4 = - 5
vertex = (3, - 5 ) → second table
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First we will evaluate: ( substitution: u = x² - y², du = - 2 y dy )
=
( than plug in x and 0 )
=
=
= 1/3 x³ ( then another integration )
= 1/3 * 1/4 = 1/12
=
=
= 1/3 x³ ( then another integration )
= 1/3 * 1/4 = 1/12
Given:
The figure of a circle.
The measure of arc SR = 75 degrees.
Measure of angle RSQ = 95 degrees.
To find:
The measure of SQ.
Solution:
Let us consider, O be the center of the circle.
According to the central angle theorem, the measure central angle on an arc is twice of inscribed angle on the corresponding angle.
Using the central angle theorem, we get
It is the central angle on major arc QR.
We know that the measure of complete central angle is 360 degrees.
The central angle on minor arc QR is:
It means the measure of arc RSQ is 170 degrees.
Therefore, the measure of arc SQ is 95 degrees.
