If we take the value of t to be 15 and then we perform the calculations of 2 times t divided by 3, we can express it all by two equations substituting the value given for t like so:
t = 15
2t/3 = 2(15)/3 = 30/3 = 10
Find 5/8 of full
find 5/8 of 64
5/8 times 64/1=320/8=160/4=80/2=40
answer is 40 gallons in the trick right now
Average rate of change can be calculated by determining the
rate of change at x = a, and at x = b
f’(x) =2 (3^x) ln(3)
f’(0) = 2 ln(3)
f’(1) = 6 ln(3)
f’(2) = 18 ln(3)
f’(3) = 54 ln(3)
Average:
at section A = [6 ln(3) – 2 ln(3)]/1 = 4 ln(3)
at section B = [54 ln(3) – 18 ln(3)]/1 = 36 ln(3)
section B is 9 times larger.
Based from the f’(x), f’(x) varies as the power of x. so the
greater of value of x, the greater the rate of change.
It would take the car 5 hours to travel 300km.
Equation used to solve: (120÷2)×6
