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kvv77 [185]
3 years ago
10

Naoya read a book cover to cover in a single session, at a rate of 55 pages per hour. After reading for 4 hours, he had 330 page

s left to read. how long is the book?
Mathematics
2 answers:
Alexxandr [17]3 years ago
7 0

Answer:

550 pages 10 hours

Step-by-step explanation:

worty [1.4K]3 years ago
6 0

Answer: There are 550 pages in the book

Explanation:

Since we have given that

Number of pages per hour Naoya read = 55

Number of hours he read the book = 4

Total number of pages he read is given by

55\times 4=220

Still there are some pages are left ,

Number of pages left = 330

So, total number of pages in the book is given by

330+220=550

Hence, there are 550 pages in the book .

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You have some turtles and some pelicans. Together there are 114 legs and a total of 34 animals. How many of each animal are ther
Ann [662]

Let t and p represent the numbers of turtles and pelicans, respectively.

... 2p + 4t = 114 . . . . . . . the number of legs is 114

... p + t = 34 . . . . . . . . . the number of animals is 34

Divide the first equation by 2 and subtract the second.

... (2p +4t)/2 - (p +t) = (114)/2 - 34

... t = 23 . . . . . . . . . . . . . . . . . . . . . . simplify

Then p = 34 - t = 11

There are 11 pelicans and 23 turtles.

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You can get to the same answer by considering the number of legs you would have if all the animals were pelicans. That would be 34*2 = 68. The is 46 fewer legs than there actually are. Each turtle that replaces one of those 34 pelicans adds 2 legs to the total, so to add 46 legs, we must replace 46/2 = 23 pelicans with turtles. That is, there are 23 turtles and 11 pelicans.

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3 years ago
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3 years ago
The triangle below is a scalene triangle which statement is true?
xz_007 [3.2K]

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2 years ago
On a farm there are three-legged-cows and chickens. There are total of 127 heads and 353 legs. How many three-legged-cows are on
olga nikolaevna [1]

Answer: There are 99 three-legged-cows  and 28 chickens.

Step-by-step explanation:

Let x be the number of three-legged-cows and y be the number of chickens.

Number of legs in chicken = 2

The according to the question, we have the following equations :-

\text{For heads }x+y=127------(1)\\\\\text{For legs }3x+2y=353------(2)

Multiplying 2 to the equation (1), we get

2x+2y=254--------(3)

Now, subtract equation (3) from (2), we get

x=353-254=99

Put x= 99 in (1), we get

99+y=127\\\\\Rightarrow\ y=127-99=28

Hence, there are 99 three-legged-cows  and 28 chickens.

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3 years ago
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