All categories

2 years ago

Fiad the sample variance and standard deviation. 21, 10, 3, 7, 11

Mathematics

1 answer:

Serggg [28]2 years ago

7 0

Answer:

SD = 5.987, Var(X) = 35.85

Step-by-step explanation:

Apply the standard deviation formula, remembering that n represents the sample size. Then, just take the square of the standard deviation to obtain the variance.

Hope this helps!

You might be interested in

00:57

prisoha [69]

<h3>Given:</h3>

h= 19 ft
r= 12 ft

h= Height
r= Radius

The volume of the given cone.

<h3>Solution:</h3>

$\large\boxed{Formula:V= \frac{1}{3}\pi{r}^{2}h}$

$\large\boxed{\red \pi \red = \red 3 \red . \red 1 \red 4}$

Let's solve!

Substitute the values according to the formula.

$V=\frac{1}{3}×3.14×{12}^{2}×19$

$\large\boxed{V=2863.68 \: {ft}^{3}}$

Therefore, the volume of the given cone is 2863.68 cubic feets.

5 0

2 years ago

The function y = 3.75 + 1.5 (x - 1) can be used to determine the cost in dollars for a taxi ride of x miles. Give the number whi

Degger [83]

Answer:

rate of change = 1.5 dollars per mile

Step-by-step explanation:

cost for travelling 1 mile = 3.75

cost 2 miles = 5.25

cost 3 miles = 6.75

cost 4 miles = 8.25

8 0

3 years ago

Read 2 more answers

Math 2 Of high school

Daniel [21]

Answer:

B. BC = 18 so ∆ABC ～ ∆DEF by SAS

Step-by-step explanation:

$\bf \cfrac{AB}{DE} = \cfrac{BC}{EF}$

$\bf \cfrac{15}{10} = \cfrac{BC}{12}$
$\bf \cfrac{3}{2} = \cfrac{BC}{12}$
$\bf BC = \cfrac{3}{2} \times 12$
$\bf 3 \times 6$
$\bf BC = 18$
$\bf \angle B = \angle \: E$

So, ∆ABC ～ ∆DEF by SAS.

7 0

1 year ago

a metal rod 9.4 meters long is cut into two piecew. One piece is 3 times as long as the other m. find the length of the longer p

Grace [21]

$x-shorter\ piece\\3x-longer\ piece\\\\x+3x=9.4\\4x=9.4\ \ \ \ \ |:4\\x=2.35\\\\3\cdot2.35=7.05\approx7.1\\\\The\ longer\ piece\ has\ 7.1\ meters$

8 0

2 years ago

Identify the lower class limits, upper class limits, class width, class midpoints, and class boundaries for the given freque

bezimeni [28]

Answer:

See explanation and results below.

Step-by-step explanation:

We have the following data:

Age (yr) when award was won Frequency 25-34 31 35-44 36 45-54 12 55-64 4 65-74 6 75-84 1 85-94 2

If we order the data we got the following result. We assume that the midpoint is given by:

$Midpoint= \frac{L.Limit +U.Limit}{2}$

The $Class.Width = U.Limit-L.Limit$

And the limits are given by the lower and upper limit.

L.Limit U.Limit Class W Midpoint Frequency Limits

25 34 34-25=9 29.5 31 [25-34]

35 44 44-35=9 39.5 36 [35-44]

45 54 54-45=9 49.5 12 [45-54]

55 64 64-55=9 59.5 4 [55-64]

65 74 74-65=9 69.5 6 [65-74]

75 84 84-75=9 79.5 1 [75-84]

85 94 94-85=9 89.5 2 [85-94]

8 0

2 years ago