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3 years ago

10

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1 answer:

user100 [1]3 years ago

8 0

From line C because the corresponding vertices are equal distance from line C

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Write an expression you could use to convert 2.5 gallons to quarts. ( need quickly plz )

KonstantinChe [14]

Gallons * 4
(Because there are 4 quarts in 1 gallon)
2.5 * 4 = 10.
There are 10 Quarts in 2.5 Gallons.

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3 years ago

The Midtown Bakery sells Chinese specialities such as pineapple buns and lotus seed buns. Day-old goods at the bakery are sold a

gayaneshka [121]

You would save $1.79

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3 years ago

Solve the equation for z <br>5z-8=32<br>A. z=4<br>B. z=4.8<br>C. z=6<br>D. z=8

nadezda [96]

Answer:

Z=8 is the answer

Step-by-step explanation:

first, you add 8 to both sides which leaves you with 5z=40. then after that you divide both sides by 5 which leaves you with 5/5z = 40/5. then buy dividing 5 by 5 its leaves you with 1 which is equal to z because blank variables equal 1. On the other side if the equation 40 by 5 is 8 so that leaves you with z=8

5 0

2 years ago

Read 2 more answers

Measure the lengths of the sides of ∆ABC in GeoGebra, and compute the sine and the cosine of ∠A and ∠B. Verify your calculations

marusya05 [52]

Answer:

$Sin \angle A =0.80$

$Cos \angle A=0.60$

$Sin \angle B =0.60$

$Cos \angle B=0.80$

Step-by-step explanation:

Given

I will answer this question using the attached triangle

Solving (a): Sine and Cosine A

In trigonometry:

$Sin \theta =\frac{Opposite}{Hypotenuse}$ and

$Cos \theta =\frac{Adjacent}{Hypotenuse}$

So:

$Sin \angle A =\frac{BC}{BA}$

Substitute values for BC and BA

$Sin \angle A =\frac{8cm}{10cm}$

$Sin \angle A =\frac{8}{10}$

$Sin \angle A =0.80$

$Cos \angle A=\frac{AC}{BA}$

Substitute values for AC and BA

$Cos \angle A=\frac{6cm}{10cm}$

$Cos \angle A=\frac{6}{10}$

$Cos \angle A=0.60$

Solving (b): Sine and Cosine B

In trigonometry:

$Sin \theta =\frac{Opposite}{Hypotenuse}$ and

$Cos \theta =\frac{Adjacent}{Hypotenuse}$

So:

$Sin \angle B =\frac{AC}{BA}$

Substitute values for AC and BA

$Sin \angle B =\frac{6cm}{10cm}$

$Sin \angle B =\frac{6}{10}$

$Sin \angle B =0.60$

$Cos \angle B=\frac{BC}{BA}$

Substitute values for BC and BA

$Cos \angle B=\frac{8cm}{10cm}$

$Cos \angle B=\frac{8}{10}$

$Cos \angle B=0.80$

Using a calculator:

$A = 53^{\circ}$

So:

$Sin(53^{\circ}) =0.7986$

$Sin(53^{\circ}) =0.80$ -- approximated

$Cos(53^{\circ}) = 0.6018$

$Cos(53^{\circ}) = 0.60$ -- approximated

$B = 37^{\circ}$

So:

$Sin(37^{\circ}) = 0.6018$

$Sin(37^{\circ}) = 0.60$ --- approximated

$Cos(37^{\circ}) = 0.7986$

$Cos(37^{\circ}) = 0.80$ --- approximated

8 0

3 years ago

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Devin brought his snails collection to school. He has 10 snails. How could he put them into 2 tanks so two classes could see the

galina1969 [7]

10 divided by 2 = 5 is one of the equations

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3 years ago