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Tanya [424]
2 years ago
10

Graph

Mathematics
1 answer:
user100 [1]2 years ago
8 0
From line C because the corresponding vertices are equal distance from line C
You might be interested in
R÷10+4=5 what does R euqe .
mrs_skeptik [129]
R=10 
because 10 divided by ten =1 +4 =5
3 0
3 years ago
Determine whether the following lines represented by the vector equations below intersect, are parallel, are skew, or are identi
KiRa [710]

Answer:

r(t) and s(t) are parallel.

Step-by-step explanation:

Given that :

the  lines represented by the vector equations are:

r(t)=⟨1−t,3+2t,−3t⟩

s(t)=⟨2t,−3−4t,3+6t⟩

The objective is to determine if the following lines represented by the vector equations below intersect, are parallel, are skew, or are identical.

NOTE:

Two lines will be parallel if \dfrac{x_1}{x_2}= \dfrac{y_1}{y_2}= \dfrac{z_1}{z_2}

here;

d_1 = (-1, \ 2, \ -3)

Thus;

r(t) = \dfrac{x-1}{-1} = \dfrac{y-3}{2}=\dfrac{z-0}{-3} = t

d_2 =(2, \ -4, \  +6)

s(t) = \dfrac{x-0}{2} = \dfrac{y+5}{-4}=\dfrac{z-3}{6} = t

∴

\dfrac{d_1}{d_2}= \dfrac{-1}{2} = \dfrac{2}{-4}= \dfrac{-3}{-6}

Hence, we can conclude that r(t) and s(t) are parallel.

6 0
3 years ago
How do you do this question?
OLEGan [10]

Step-by-step explanation:

∫ dt / (cos²(t) ⁹√(1 + tan(t)))

If u = 1 + tan(t), then du = sec²(t) dt.

∫ du / ⁹√u

∫ u^(-1/9) du

9/8 u^(8/9) + C

9/8 (1 + tan(t))^(8/9) + C

7 0
3 years ago
Can someone please help me w this. thx lol :)<br><br> even dropping the link to the answers is fine
Sphinxa [80]
It’s a black screen

7 0
2 years ago
I don't get this I need help?
Aleks04 [339]

Answer: 4r^2

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
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