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allsm [11]
3 years ago
9

What does 40 divided by 1+3-(3x7)+7-5 equal?

Mathematics
1 answer:
JulijaS [17]3 years ago
5 0
40/[1+3-(3x7)+7-5)
= 40/[1+3-21+7-5]
=40/[-15]
= - (8/3)
-2 2/3
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Please help!!! Write 4x^2=12 in standard form?
Andru [333]

Answer:

x =  \sqrt{3}

Step-by-step explanation:

4x^2=12

x^2=12/4

x= root 3

3 0
3 years ago
Which of the following are solutions to the equation below?
Luden [163]

Answer:

c) -4/5

d) 4/5

Step-by-step explanation:

The given equation is 25x^2 -16 = 0

Adding 16 on both sides, we get

25x^2 = 16

Dividing both sides by 25, we get

x^2 = 16/25

Taking square root on both sides, we get

x = √(16/25)

x = ±4/5

Therefore, x = 4/5 and x = -4/5

Answers: C) and D)

Hope this will helpful to understand the concept.

Thank you.

4 0
3 years ago
Find the reference angle for 497°<br> A) 137°<br> B)133°<br> C) 47°<br> D) 43°
Mila [183]
Reference angle is 137
4 0
3 years ago
Read 2 more answers
Write the following sets in set-builder notation: (a) The set of all humans whose first name is Tanya or Nelson.
Ulleksa [173]

Answer:

Step-by-step explanation:

Set is a well defined collection of objects .

We can express set in roaster form or set - builder form

<u>Roaster Form</u>

We express elements within curly brackets using commas between the elements .

<u>Set Builder Form</u>

In set builder form , all the elements of the set possess a common property which is not possess by elements outside the set .

We describe the elements of set using a symbol x which is followed by a colon . After colon , we write property possessed by the element and then enclosed the description within curly brackets .

(a)The set of all humans whose first name is Tanya or Nelson

We need to write this one in set builder form .

Define set as follows : { x ∈ H : H is set of all the humans and x is either Tanya or Nelson }

5 0
3 years ago
What are the solutions to the quadratic equation below x^2+20x+100=7​
aleksandrvk [35]

First you must have the quadratic equal to zero. In order to do this you must subtract 7 to both sides

x^2 + 20x + (100 - 7) = 7 - 7

x^2 + 20x + 93 = 0

Now you must find two numbers who's sum equals 20 and their multiplication equal 93

Are there any? NO!

This means that you have to use the formula:

\frac{-b±\sqrt{b^{2} - 4ac} }{2a}

In this case:

a = 1

b = 20

c = 93

\frac{-(20) plus/minus\sqrt{20^{2} - 4(1)(93)} }{2*1}

\frac{-20 plus/minus\sqrt{400 - 372} }{2}

\frac{-20 plus/minus\sqrt{28} }{2}

^^^We must simplify √28

√28 = 2√7

so...

\frac{-20 plus/minus 2\sqrt{7} }{2}

simplify further:

-10 plus/minus\sqrt{7

-10 + √7

or

-10 - √7

***plus/minus = ±

Hope this helped!

~Just a girl in love with Shawn Mendes

7 0
3 years ago
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