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Marat540 [252]
3 years ago
9

A surgical procedure requires choosing among four alternative methodologies. The first can result in five possible outcomes, the

second can result in two possible outcomes, and the remaining methodologies can each result in four possible outcomes. What is the total number of outcomes possible?
Mathematics
1 answer:
Illusion [34]3 years ago
4 0

Answer:

15 possible outcomes

Step-by-step explanation:

Since each one of these methodologies are not related to one another and they do not need to be chosen in any order or consecutively then the possible outcomes would only need to be added all together to calculate the total possible outcomes. Since each outcome is independent. Therefore,

m1 = 5 outcomes

m2 = 2 outcomes

m3 = 4 outcomes

m4 = 4 outcomes

5 + 2 + 4 + 4 = 15

we can see that there are a total of 15 possible outcomes

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3 years ago
Y=6x4 + 7x2 and x = vw +1
belka [17]

Answer:

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Step-by-step explanation:

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y=6x^4+7x^2\\10=6(\sqrt{w+1})^4+7(\sqrt{w+1})^2\\10=6(w+1)^2+7(w+1)\\10=6(w^2+2w+1)+7w+7\\10=6w^2+12w+6+7w+7\\0=6w^2+19w+3

Solve for w with the quadratic formula:

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After simplifying, we get either w=-1/6 or w=-3.

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2 years ago
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Answer:

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Step-by-step explanation:

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4 0
3 years ago
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