A vertical right circular cylindrical tank measures 20 ft high and 12 ft in diameter. It is full of liquid weighing 62.4 lb divi
1 answer:
Answer:
Step-by-step explanation:
Work done is given as the product of force and distance.
The liquid in the cylindrical tank weighs 62.4 lb/ft^3.
This means that each ft^3 of the tank has 62.4 lb of the liquid.
To find the wight of the liquid in the entire tank, we multiply 62.4 by the volume of the cylindrical tank.
The volume of a cylinder is given as:
where r is its radius and h is its height
The radius of the tank is 6 ft (since its diameter is 12 ft) and its height is 20 ft.
Therefore, the weight of the liquid in the tank is given as:
This weight is a force.
The height of the tank is 20 ft.
Therefore, the work done in pumping the liquid to the top of the tank is:
W = 2261.95 * 20 = 45239 ft.lb
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Let the amount invested with 5% interest be x
Therefore, the amount invested with 6% interest will be (6000-x)
It is given that the total interest earned yearly is $337.5. Thus, the equation of interest will be:
Multiplying both sides by 100 we get:
Subtracting both sides by 36000 we get:
Thus, the amount invested at 5% is $2250
Therefore, the amount invested at 6% will be $(6000-2250)=$3750
Answer:
The scale factor of the following dilation is, 0.5
Step-by-step explanation:
The rule of dilation with scale factor k is given by:
As per the statement:
Given the following dilation:
(10, 0) → (5, 0) .....[1]
We have to find the scale factor.
Using the above rule we have;
Now compare this with equation [1] we have;
(10k, 0) = (5, 0)
⇒10k = 5
After solving we get;
Therefore, the scale factor of the following dilation is, 0.5