Question

A vertical right circular cylindrical tank measures 20 ft high and 12 ft in diameter. It is full of liquid weighing 62.4 lb divided by ft cubed. How much work does it take to pump the liquid to the level of the top of the​ tank?

Answer 1

Answer:

Step-by-step explanation:

Work done is given as the product of force and distance.

The liquid in the cylindrical tank weighs 62.4 lb/ft^3.

This means that each ft^3 of the tank has 62.4 lb of the liquid.

To find the wight of the liquid in the entire tank, we multiply 62.4 by the volume of the cylindrical tank.

The volume of a cylinder is given as:

$V = \pi r^2h$

where r is its radius and h is its height

The radius of the tank is 6 ft (since its diameter is 12 ft) and its height is 20 ft.

Therefore, the weight of the liquid in the tank is given as:

$V = \pi * 6^2 * 20 = 2261.95 lb$

This weight is a force.

The height of the tank is 20 ft.

Therefore, the work done in pumping the liquid to the top of the tank is:

W = 2261.95 * 20 = 45239 ft.lb