An intersection point, is a shared coordinate. If the equations share a coordinate we can say they are "equal". There are two ways (algebraically) to find this point. Substitution or linear combination. Because the coefficients are different, let's use linear combination
First stack the equations on top of each other.
2x + 3y = 5
3x + 4y = 6
Next let's manipulate one or both of the equations to get coefficients that are equal, but opposite. For this I'm going to turn the coefficient of x into 6 and -6 respectively by multiplying the first equation by 3 and the second by -2 to get
6x + 9y = 15
-6x -8y = -12
Now we can combine the equations with addition and the x's will cancel leaving a single variable (which we can solve)
y = 3
Now plug this back into either original equation to find the x coordinate.
2x + 3(3) = 5
2x + 9 = 5
2x = -4
x = -2.
So your intersection point is (-2,3)
Answer:
c=2
Step-by-step explanation:
7-4c=3c-7
7+7=3c+4c
14=7c
Dividing both sides by 7
c=2
CHECK:
Putting c in the above equation
7-4(2)=3(2)-7
7-8=6-7
-1=-1
Hence the above solution satisfies the given equation
P/8=14/3
P=14*8/3
P=37.3333
Answer:
The equation represented by the ordered pair is;
y = 2^(5-x)
Step-by-step explanation:
Here, we want to write the equation represented by the ordered pairs
From what we have in the question, we can see that while the x-values increase in arithmetic progression of 1
The y-values decrease in order of two geometrically
Thus, the equation is;
y = 2^(5-x)
