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emmainna [20.7K]
3 years ago
11

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Mathematics
2 answers:
snow_lady [41]3 years ago
6 0
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Andre45 [30]3 years ago
4 0

i want free brainliest

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The table represents the observed number of leaves y on x branches of a tree. Calculate the rate of change between 3 and 4 branc
Dennis_Churaev [7]

Answer:

<h2>25</h2>

Step-by-step explanation:

The rate of change of number of tree y on x branches of a tree is expressed as shown;

m = Δy/Δx where;

m is the rate of change

Δy is the change in number of leaves  between 3 and 4

Δx is change in number of branches  between 3 and 4

m = Δy/Δx = y₂-y₁/x₂-x₁

From table between 3 and 4, y₂ = 100, y₁ = 75, x₂ = 4, x₁ = 3

m = 100-75/4-3

m = 25/1

m = 25

<em>Hence the rate of change between 3 and 4 branches is 25</em>

5 0
2 years ago
PLZ I NEED HELP ANSWER QUICK
My name is Ann [436]

Theres always 180 degrees in a flat line angle thingy you need answers fast so im not looking up what its called but 180-125=55 and then you 55-1=54 then 54/3=18!!!!!

6 0
2 years ago
Which whole number is closest to the value of square root of 54?
Blababa [14]
The answer for this problem is 7
3 0
3 years ago
Read 2 more answers
A rare form of malignant tumor occurs in 11 children in a​ million, so its probability is 0.000011. Four cases of this tumor occ
Shkiper50 [21]

Answer:

a) The mean number of cases is 0.14608 cases.

b) The probability that the number of cases is exactly 0 or 1 is 0.990.

c) The probability of more than one case is 0.010

d) No, because the probability of more than one case is very small

Step-by-step explanation:

We can model this problem with a Poisson distribution, with parameter:

\lambda=r*t=0.000011*13,280=0.14608

a) The mean amount of cases is equal to the parameter λ=0.14608.

b) The probability of having 0 or 1 cases is:

P(k=0)=\frac{\lambda^0 e^{-\lambda}}{0!}=\frac{1*0.864}{1} =0.864\\\\ P(k=1)=\frac{\lambda^1 e^{-\lambda}}{0!}=\frac{0.14608*0.864}{1} =0.126\\\\P(k\leq1)=0.864+0.126=0.990

c) The probability of more than one case is:

P(k>1)=1-P(k\leq 1)=1-0.990=0.010

d) The cluster of 4 cases can not be due to pure chance, as it is a very high proportion of cases according to the average rate. Just having more than one case has a probability of 1%.

7 0
3 years ago
Solve 5m − 3h = 45 for h. Show your work.
mezya [45]

5m − 3h = 45

Subtract 5m from both sides

-3h = 45 - 5m

Divide both sides by -3

h = (45 - 5m)/ -3

h = -15 + 5m/3

5 0
3 years ago
Read 2 more answers
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