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vodka [1.7K]
3 years ago
9

What are variable terms

Mathematics
1 answer:
eduard3 years ago
8 0

Answer:

The following tells what variable terms are and a explanation. I hope this is helpful

Step-by-step explanation:

Each expression is made up of terms. A term can be a signed number, a variable, or a constant multiplied by a variable or variables. ... In , the terms are: 5x, 3y, and 8. When a term is made up of a constant multiplied by a variable or variables, that constant is called a coefficient.

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<img src="https://tex.z-dn.net/?f=f%20-%20354%20%3D%201221" id="TexFormula1" title="f - 354 = 1221" alt="f - 354 = 1221" align="
alukav5142 [94]

f-354=1221           <em>add 354 to both sides</em>

f+354-354=1221+354\\\\\boxed{f=1,575}\to\boxed{D.}

6 0
3 years ago
PLEASE HELPP:
kirill [66]

The correct answer to your question is "A".

3 0
3 years ago
Read 2 more answers
Martha changed 350 US dollars into 385 Australian dollars. How many Australian dollars did she receive for each US dollar?
Leni [432]

Answer:

For each US dollar she gets 1.1 AUS dollars

Step-by-step explanation:

350US for 385AUS

350:385 divide by 350

1 : 1.1

6 0
3 years ago
After being rearranged and simplified, which of the following equations could be solved using the quadratic formula?
dmitriy555 [2]
A. 2x^2 - 3x + 10 = 2x + 21
2x^2 - 3x - 2x + 10 - 21 = 0
2x^2 - 5x - 11 = 0                              (quadratic equation)

2x^2 - 6x - 7 = 2x^2
2x^2 - 2x^2 - 6x - 7 = 0
-6x - 7 = 0                                          (not a quadratic equation)

5x^2 + 2x - 4 = 2x^2
5x^2 - 2x^2 + 2x - 4 = 0
3x^2 + 2x - 4                                      (quadratic equation)

5x^3 - 3x + 10 = 2x^2
5x^3 - 2x^2 - 3x + 10 = 0                    (not a quadratic equation)

Therefore, options a and c can be solved using the quadratic formula.
3 0
3 years ago
Use the substitution method to solve the system of equations.
grandymaker [24]
Insert 3x - 7 for y in 15x - 5y = 14
15x - 5(3x - 7) = 14
15x - 15x + 35 = 14
0 = -21
There is no solution.
5 0
3 years ago
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