Since they are congruent, cpctc,
just set the congruent parts equal to each other.
so 2x-20=30
and
15=3y-9
<span>-3(5+8r)=33-8r
-15 - 24r = 33 - 8r
-15 - 33 = - 8r + 24r
-48 = 16r
-48/16 = r
-3 = r
r = -3</span>
Use pythagoras
d = √(Δx² + Δy²)
d = √(12-2)² + (9-4)²
d = √(10² + 5²)
d = √(100 + 25)
d = √125
d = 5√5
d = 5 × 2.236
d = 11.18
The nearest tenth is 11.2, so the distance is near to 11.2
Answer:
x = 2
Step-by-step explanation:
<em>Distribute</em>
3 (−4) = 2 (−2+1)
3 − 12 = 2 (-2x +1)
<em>Distrubute again</em>
3x - 12 = -4x + 2
<em>Add twelve to both sides of the equation</em>
<em>Simpfly</em>
3x = -4x + 14
<em>Add 4x to both sides of the equation</em>
<em>simpfly</em>
7x = 14
<em>Divide both sides of the equation by the same term</em>
<em>Simpfly</em>
x = 2
