Hello! The answer to this question is: A = -2
Lauren =l
David=d
Bethany's =x
Amanda =y
l=x+13
d=y+11
lx=2y
<span>(x+13)x=2y
</span>
![2y=x^2+13x](https://tex.z-dn.net/?f=2y%3Dx%5E2%2B13x)
![y= \frac{1}{2}(x^2+13x)](https://tex.z-dn.net/?f=y%3D%20%5Cfrac%7B1%7D%7B2%7D%28x%5E2%2B13x%29)
or
![y= \frac{x^2}{2}+ \frac{13}{2}x](https://tex.z-dn.net/?f=y%3D%20%5Cfrac%7Bx%5E2%7D%7B2%7D%2B%20%5Cfrac%7B13%7D%7B2%7Dx%20)
(x-20)(l-20)=d
<span>(x-20)(x+13-20)=y+11 </span><span>
</span>
![y+11=(x-20)(x-7)](https://tex.z-dn.net/?f=y%2B11%3D%28x-20%29%28x-7%29)
![y+11=x^2-27x+140](https://tex.z-dn.net/?f=y%2B11%3Dx%5E2-27x%2B140)
![y=x^2-27x+129](https://tex.z-dn.net/?f=y%3Dx%5E2-27x%2B129)
so I believe its b
Hope this helps :)
Answer:
wait wait explain on what i need to do
Step-by-step explanation:
Answer:
None of the above
Step-by-step explanation: