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3 years ago

8

You have 8 cups of flour. A recipe calls for 2/3cup of flour. Another recipe calls for 1/4 cup of flour. How much flour do you h

ave left after making the recipes?

1 answer:

Sonja [21]3 years ago

6 0

There will be 5 more because 8-2-1 =5

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Solve for x.<br><br><img src="https://tex.z-dn.net/?f=x%20%2B%206%20-%202x%20%3D%20x%20-%2024" id="TexFormula1" title="x + 6 - 2

zhenek [66]

<em>Greetings from Brasil...</em>

First degree equation. The variables are in the 1st member and the numbers in the 2nd member.

X + 6 - 2X = X - 24

X - 2X - X = - 24 - 6

- 2X = - 30

<h2>X = 15</h2>

7 0

3 years ago

An ice cream shop sold 12,789 chocolate and 9,324 cookie dough cones. They sold 1,078 more peanut butter cones than cookie dough

juin [17]

12,789 chocolate
9,324 Cookie Dough
10,402 Peanut Butter Cones
13,788 Vanilla

46,303 in total

3 0

3 years ago

The frequency of the musical note C4 is about 261.63 Hz. What is the frequency of the note a perfect fifth below C4?

kolbaska11 [484]

Answer:

The frequency of the note a perfect fifth below C4 is;

B- 174.42 Hz

Step-by-step explanation:

Here we note that to get the "perfect fifth" of a musical note we have to play a not that is either 1.5 above or 1.5 below the note to which we reference. Therefore to get the frequency of the note a perfect fifth below C4 which is about 261.63 Hz, we have

1.5 × Frequency of note Y = Frequency of C4

1.5 × Y = 261.63

Therefore, Y = 261.63/1.5 = 174.42 Hz.

6 0

2 years ago

What happens when demand exceeds supply

melomori [17]

<span>The price usually goes up. If lots of people want something, you have to pay more to get it.</span>

3 0

3 years ago

Read 2 more answers

Find the dimensions of an open rectangular box with a square base that holds 2000 cubic cm and is constructed with the least bui

Vesnalui [34]

<h3>The dimensions of the given rectangular box are:</h3><h3>L = 15.874 cm , B = 15.874 cm , H = 7.8937 cm</h3>

Step-by-step explanation:

Let us assume that the dimension of the square base = S x S

Let us assume the height of the rectangular base = H

So, the total area of the open rectangular box

= Area of the base + 4 x ( Area of the adjacent faces)

= S x S + 4 ( S x H) = S² + 4 SH ..... (1)

Also, Area of the box = S x S x H = S²H

⇒ S²H = 2000

$\implies H = \frac{2000}{S^2}$

Substituting the value of H in (1), we get:

$A = S^2 + 4 SH = S^2 + 4 S(\frac{2000}{S^2}) = S^2 + (\frac{8000}{S})\\\implies A = S^2 + (\frac{8000}{S})$

Now, to minimize the area put :

$(\frac{dA}{dS} ) = 0 \implies 2S - \frac{8000}{S^2} = 0\\\implies S^3 = 4000\\\implies S = 15.874 \approx 16 cm$

Putting the value of S = 15.874 cm in the value of H , we get:

$\implies H = \frac{2000}{S^2} = \frac{2000}{(15.874)^2} = 7.8937 cm$

Hence, the dimensions of the given rectangular box are:

L = 15.874 cm

B = 15.874 cm

H = 7.8937 cm

3 0

3 years ago