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andriy [413]
3 years ago
9

Is this true? if not what’s the answer asap!

Mathematics
1 answer:
tensa zangetsu [6.8K]3 years ago
4 0

Answer:

(x {}^{ - 4} ) {}^{2} \:  =  \: x {}^{ - 4 \times 2 }   =  \: x {}^{ - 8}  =  \:  \frac{1}{ x {}^{8}  }

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But yeah, generally speaking, "real analysis" and "advanced calculus" are synonyms. Schools never offer courses with *both* names, and whichever one they do offer, it is probably a class that covers the subject matter of calculus, but in a way that emphasizes the logical structure of the material (in particular, precise definitions and proofs) over just doing calculation.

My impression is that "advanced calculus" is an "older" name for this topic, and that "real analysis" is a somewhat "newer" name for the same topic. At least, most textbooks currently written in this area seem to have titles with "real analysis" in them, and titles including the phrase "advanced calculus" are less common. (There are a number of popular books with "advanced calculus" in the title, but all of the ones I've seen or used are reprints/updates of books originally written decades ago.)

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3 years ago
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