Answer: 0.2
Step-by-step explanation:
We know that , the probability density function for uniform distribution is given buy :-
, where x is uniformly distributed in interval [a,b].
Given : The time to process a loan application follows a uniform distribution over the range of 8 to 13 days.
Let x denotes the time to process a loan application.
So the probability distribution function of x for interval[8,13] will be :-
Now , the probability that a randomly selected loan application takes longer than 12 days to process will be :-
![\int^{13}_{12}\ f(x)\ dx\\\\=\int^{13}_{12}\dfrac{1}{5}\ dx\\\\=\dfrac{1}{5}[x]^{13}_{12}\\\\=\dfrac{1}{5}(13-12)=\dfrac{1}{5}=0.2](https://tex.z-dn.net/?f=%5Cint%5E%7B13%7D_%7B12%7D%5C%20f%28x%29%5C%20dx%5C%5C%5C%5C%3D%5Cint%5E%7B13%7D_%7B12%7D%5Cdfrac%7B1%7D%7B5%7D%5C%20dx%5C%5C%5C%5C%3D%5Cdfrac%7B1%7D%7B5%7D%5Bx%5D%5E%7B13%7D_%7B12%7D%5C%5C%5C%5C%3D%5Cdfrac%7B1%7D%7B5%7D%2813-12%29%3D%5Cdfrac%7B1%7D%7B5%7D%3D0.2)
Hence, the probability that a randomly selected loan application takes longer than 12 days to process = 0.2
Step-by-step explanation:
sin = 15/17
cos = -8/17
tan = -15/8
csc = 17/15
sec = -17/8
cot = -8/15
<u>The domain</u> of the <u>function</u> are all possible values for <u>variable</u> x and <u>the range</u> of the function are all possible values for the variable y.
Consider the parrent function 
The domain of this function is 
the range of this function is 
1. Translate this function 5 units to the right. After this translation the function becomes
2. Reflect previous function about the x-axis, then the expresssion of the new function is
The range of the function will be 
3. Translate the function 
3 units up, then you will get the function
The domain of this function is 
the range of this function is 
Answer:
