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Brums [2.3K]
4 years ago
9

Guys i really need help. i am new to these type of math problems Please help me

Mathematics
1 answer:
tankabanditka [31]4 years ago
8 0
7.
I: when no unit, assume radians

II: hmm, 0 to pi/2 radians is 1st quadrant, pi/2 to pi is 2nd, pi to 3pi/2 is 3rd and 3pi/2 to 2pi is 4th
pi/2<1.57<pi so it is in 2st quadrant

III:
cos is negative here because cos is the x axis

IV. no because the value of cos(1.75rad) should be negative




8.
I: from 0 to 90 is 1st
from 90 to 180 is 2nd
from 180 to 270 is 3rd
from 270 to 360 is 4th

so it is in 2nd quadrant


II: sin is positive here because sin is the y axis

III: sin should be positive here so a negative value is not reasonable

IV: maybe she put 125 without putting the degrees and the calculator thought that it was radians
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Which is the graph of y= 2(x-3)^2 +2
WINSTONCH [101]

The graph of y = 2(x - 3)² + 2 can be seen in the attached picture. This problem can be solved through the concept of parabola and transformation.

<h3>Further explanation</h3>

<u>The Problem:</u>

Which is the graph of y = 2(x - 3)² + 2?

<u>Question-1:</u>

How to make a graph y = 2 (x - 3) ² + 2 through the concept of a parabola.

<u>The Process:</u>

The equation of a parabola is given by \boxed{ \ y = a(x - h)^2 + k \ }.

Keep in mind the following points:

  • vertex point at (h, k)
  • axis of symmetry at x = h
  • a > 0 the parabola opens upward
  • a < 0 the parabola opens downward
  • the y-intercept is \boxed{ \ y = ah^2 + k \ } at x = 0.

From our case it can be concluded as follows:

  • the graph of y = 2(x - 3)² + 2 opens upward
  • vertex point at (3, 2)
  • axis of symmetry at x = 3
  • the y-intercept is 2(3²) + 2 = 20 or in coordinates of (0, 20)

<u>Question-2:</u>

How to make the graph of y = 2(x - 3)² + 2 through the transformation.

<u>The Process:</u>

To plot the graph of y = 2(x - 3) ² + 2 we apply for the following transformation order:

Step-1: clearly, to obtain the graph of y = (x - 3)² we shift the graph of y = x² to the right 3 units.

Step-2: to obtain the graph of y = 2(x - 3)², we stretch the graph of y = (x - 3)²  by a factor of 2 (in other words, multiply each y-coordinate by 2).

Step-3: finally, to obtain the graph of y = 2(x - 3)² + 2 we shift the graph of y = 2(x - 3)² upward 3 units.

Thus the construction of the graph y = 2 (x - 3) ² + 2 is completed.

The graph of y = 2(x - 3) ² + 2 is drawn by the combination of shifting the graph of y = x² to the right 3 units and upward 2 units, and also stretch by a factor of 2. Between vertical shift and stretch steps, it is the same whatever steps are taken first.

- - - - - - - - - -

Notes

  • The transformation of graphs is changing the shape and location of a graph.  
  • There are four types of transformation geometry: translation (or shifting), reflection, rotation, and dilation (or stretching/shrinking).  
  • In this case, the transformation is shifting horizontally and vertically and also stretching vertically.

In general, given the graph of y = f(x) and v > 0, we obtain the graph of:  

  • \boxed{ \ y = f(x) + v \ } by shifting the graph of \boxed{ \ y = f(x) \ } upward v units.  
  • \boxed{ \ y = f(x) - v \ } by shifting the graph of \boxed{ \ y = f(x) \ } downward v units.  

That's the vertical shift, now the horizontal one. Given the graph of y = f(x) and h > 0, we obtain the graph of:  

  • \boxed{ \ y = f(x + h) \ } by shifting the graph of \boxed{ \ y = f(x) \ } to the left h units.  
  • \boxed{ \ y = f(x - h) \ } by shifting the graph of \boxed{ \ y = f(x) \ } to the right h units.

Hence, the combination of vertical and horizontal shifts is as follows:  

\boxed{ \ y = f(x \pm h) \pm v \ }  

The plus or minus sign follows the direction of the shift, i.e., up-down or left-right .

Notice the following definitions for stretch and shrink.

  • In general, given the graph of \boxed{y = f(x)}, we obtain the graph of \boxed{y = cf(x)} by stretching \boxed{ \ c > 1 \ } or shrinking \boxed{ \ 0 < c < 1 \ } the graph of \boxed{y = f(x)} vertically by a factor of c.
  • In general, given the graph of \boxed{y = f(x)}, we obtain the graph of \boxed{y = f(cx)} by stretching \boxed{ \ 0 < c < 1 \ } or shrinking \boxed{ \ c > 1 \ } the graph of \boxed{y = f(x)} horizontally by a factor of c.
<h3>Learn more  </h3>
  1. What is the y-intercept of the quadratic function  f(x) = (x – 6)(x – 2)? brainly.com/question/1332667
  2. Transformations that change the graph of (f)x to the graph of g(x) brainly.com/question/2415963
  3. Which statement correctly describes the graph  brainly.com/question/10929552

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