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bagirrra123 [75]
3 years ago
7

X+2y=19 and x+y=13 in substitution methood​

Mathematics
1 answer:
densk [106]3 years ago
3 0
X=7, y=6. that’s your answer!
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Write an explicit formula for an, the n^th<br> term of the sequence 2, 4, 6, ....
Eduardwww [97]

Answer:

a_n=2n

Step-by-step explanation:

The given sequence is 2, 4, 6, ....

We need to write an explicit formula for a_n. The firts term is 2, second term is 4 and third term is 6 and so on.

Each term is 2 greater than the term before it. Thus we can write it as follows :

a_n=2n

Where

n = 1,2,3....

Hence, the explicit formula is a_n=2n.

5 0
3 years ago
Ummmmm??? Is it c? Irdk
bija089 [108]

Answer:

Yes

Step-by-step explanation:

8 0
3 years ago
I NEED HELP ASPAP!!!!
Gnesinka [82]
4 is the answer king have a good day
5 0
3 years ago
I just need a little help​
iris [78.8K]

Answer:  

your answer should be 2 and 1/4ths

Step-by-step explanation

2 and 1/4ths bc 5 is more than 4 and there is already a whole so there for there are going to be 2 wholes then there are still parts left over and its out of 4 and there is only one left over so there for it would be 1/4ths.

7 0
3 years ago
Find an equation of the set of all points equidistant from the points A(−3, 6, 3) and B(4, 1, −1). Describe the set.
valentinak56 [21]

Answer:

See below

Step-by-step explanation:

I will describe this set in R³. Let P=(x,y,z) be a point equidistant to A and B, that is, the distance from P to A is equal to the distance from P to B.

First, using the usual distance formula, the distance from P to A is equal to d(P,A)=\sqrt{(x-(-3))^2+(y-6)^2+(z-3)^2}=\sqrt{(x+3)^2+(y-6)^2+(z-3)^2}

On the other hand, the distance form P to B is equal to d(P,B)=\sqrt{(x-4)^2+(y-1)^2+(z-(-1))^2}=\sqrt{(x-4)^2+(y-1)^2+(z+1)^2}

P is equidistant from A and B if and only if P satisfies the equation d(P,A)=d(P,B), that is,

\sqrt{(x+3)^2+(y-6)^2+(z-3)^2}=\sqrt{(x-4)^2+(y-1)^2+(z+-1)^2}

Take the square in both sides of this equation to get

(x+3)^2+(y-6)^2+(z-3)^2=(x-4)^2+(y-1)^2+(z+1)^2

(x+3)^2-(x-4)^2+(y-6)^2-(y-1)^2+(z-3)^2-(z+1)^2=0

You can simplify using difference of squares and multiplying like this:

(7)(2x-1)+(-5)(2y-7)+(-4)(2z-2)=0

14x-10y-8z+36=0

which is the equation of a plane.

4 0
4 years ago
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