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anygoal [31]
3 years ago
14

An inlet pipe on a swimming pool can be used to fill the pool in 40 hours. The drain pipe can be used to empty the pool in 42 ho

urs. If the pool is 23 filled and then the inlet pipe and drain pipe are opened, how long from that time will it take to fill the pool?
Mathematics
1 answer:
statuscvo [17]3 years ago
6 0

Answer:

Pool will be filled in 280 hours

Step-by-step explanation:

Inlet pipe fills in  40 hours = 1 pool

Inlet pipe fills in 1 hours = \frac{1}{40}

Drain pipe empty in 42 hours = 1 pool

Drain pipe empty in 1 hour =  \frac{1}{42}

If both pipes are opened together

 then in pool fills in 1 hour =  \frac{1}{40} -  \frac{1}{42}

      on simplifying the right side ,we get  \frac{42-40}{(40)(42)}

                                                                 =      \frac{2}{(40)(42)}

                                                                 =     \frac{1}{840}

      \frac{1}{840}  pool fills in 1 hour

                       1 pool will be filled in 840 hours

    \frac{2}{3}     pool is filled

empty pool =  1 - \frac{2}{3} =  \frac{1}{3}

therfore  \frac{1}{3} pool will be filled in     \frac{1}{3}X 840 =

                                                                                           = 280 hours

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sveta [45]

Answer:

It is the first one

Step-by-step explanation:

6 0
3 years ago
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C) If f(3x + 4)=5x + 8, find f '(x) and f(3)​
PIT_PIT [208]

Answer:

f(3x + 4) = 5x + 8

⇔ f(3x + 4) = \frac{5}{3}(3x+\frac{24}{5})

⇔ f(3x + 4) = \frac{5}{3}(3x+4+\frac{4}{5})

⇒ f'(x) = \frac{5}{3}(x+\frac{4}{5})

=> f(3) = \frac{5}{3}(3+\frac{4}{5})= \frac{19}{3}

Step-by-step explanation:

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3 years ago
Hi I need answer please. I will mark brainliest who can answer thankyou...​
DochEvi [55]

Answer:

  • a) (0,0), (-4, 1), (-1,2)
  • b) None

Step-by-step explanation:

  • <em>There are two ways of solving similar problems. One- substitute x and y with respective coordinates and verify if the inequalities are correct. Two- graph the lines and see if the points are in the intersection zones.</em>
  • <em>We'll go with the first method. </em>
  • <em>Remember both inequalities should be correct for the same point to accept it as a solution.</em>

<u>Given points </u>

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<h3>a) <u>The system of inequalities</u></h3>
  • y > x - 1
  • y < -1/2x + 2

<u>Point (0,0)</u>

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<u>Point (-4,1)</u>

  • 1 > -4 - 1 = -5 - correct
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<u>Point (-1,2)</u>

  • 2 > -1 - 1= -2 - correct
  • 2 < -1/2(-1) + 2 = 2.5 - correct
  • Yes
<h3>b) <u>The system of inequalities</u></h3>
  • x - 2y ≥ 4
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<u>Point (0, 0)</u>

  • 0 - 2(0) = 0 ≥ 4 - incorrect
  • 2(0) - 0 = 0  ≥ -1 - correct
  • No

<u>Point (-4, 1)</u>

  • -4 - 2(1) = - 6 ≥ 4 - incorrect
  • 2(-4) - 1 = - 9 ≥ -1  - correct
  • No

<u>Point (-1,2)</u>

  • -1 - 2(2) = -5  ≥ 4 - incorrect
  • 2(-1) - 2 = - 4 ≥ -1  - correct
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3 years ago
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First you can add the two functions together, since that is what (h+k) is asking us to do. 

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