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tatyana61 [14]
3 years ago
12

There were 567 children eating lunch there was 323 children drinking milk and 136 children drinking orange juice the rest of the

children were drinking apple juice how many children were drinking apple juice
Double the amount of kids drinking apple juice were eating pizza for lunch if a pizza lunch costs $2 how much money was spent on pizza that day
Mathematics
1 answer:
ahrayia [7]3 years ago
7 0

Answer:

108 children were drinking apple juice. $432 were spent on pizza.

Step-by-step explanation:

How many children were drinking apple juice:

567 - 323 - 136 = 108

How many children were eating pizza:

108 * 2 = 216

How much was spent on pizza:

216 * $2 = $432

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5 + 6 - (-3) - 8 + 4 -3
Komok [63]
Okay, so -

We have one very important thing here. This little part <em>6 - (-3). </em>

Now, it's essential to remember that when we have two negatives like this, we simply draw a line straight down. It becomes a positive! 

So, our question is essentially <em>5 + 6 + 3 - 8 + 4 - 3 = ?</em> instead of <em>5 + 6 - (-3) - 8 + 4 - 3!</em> =)

With that in mind, we simply solve left to right. 

<em>11 + 3 - 8 + 4 - 3 = ?</em>

<em>14 - 8  + 4 - 3 = ?</em>

<em>6 + 4 - 3 = ?</em>

<em>10 - 3 = ?</em>

<em>7</em> is our final answer! =)
6 0
3 years ago
At a hardware store they can cut a rope off of a big roll so you can buy any length you like. the cost of 6 feet of rope is 7.50
konstantin123 [22]

Answer:

first you'd need to divide 7.50 by 6 which will get you (7.50÷6=1.25) then you would need to multiply 1.25 by 50 which will get you $62.50 (1.25×50=62.5).

8 0
3 years ago
What are the possible numbers of positive, negative, and complex zeros of f(x)= -x^6 + x^5 - x^4 + 4x^3 - 12x^2 + 12?
inn [45]
Using Descartes' Rule of Signs:
The signs are: - + - + - +
There are 5 signs changes in this sequence, so there could be either 5, 3, or 1 positive roots.
If we negate the terms with odd numbers (x^5, x^3), we end up with the signs: - - - - - +
Since there is 1 sign change, there can be only 1 negative root.
This means the positive and negative roots can either be 6, 4, or 2.
Since the total number of roots cannot exceed 6, there are either 0, 2, or 4 complex roots.
6 0
3 years ago
Find g(1) if g(x) =x^2+1​<br>A.4<br>B.2<br>C.3
kodGreya [7K]

Answer:

B.2

Step-by-step explanation:

g(1) if g(x) =x^2+1

= x^2 + 1 = (1)^2 + 1 = 1 + 1 = 2

8 0
3 years ago
Read 2 more answers
jerome tries to find the value of the expression 3-6+5 by first applying the communtative property. he rewrites the expression a
slega [8]

The commutative property is a property of <em>addition</em>, not of <em>subtraction</em>. It can work in a subtraction problem if you keep the sign with the number, so you're adding positive and negative numbers.

3 - 6 + 5

= (3) + (-6) + (5)

= (3) + (5) + (-6)

= 3 + 5 - 6

5 0
4 years ago
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