Answer:
h = 6
Step-by-step explanation:
Given he area of the banner expressed as;
A = ℎ(2ℎ−2)
h is the height of the banner
A is the area = 60
Substitute
60 = ℎ(2ℎ−2)
60 = 2h² - 2h
30 = h² - h
h²-h-30 = 0
Factorize;
h²-6h+5h-30 = 0
h(h-6)+5(h-6) = 0
(h-6)(h+5) = 0
h - 6 = 0 and h+5 = 0
h = 6 and -5
Since the height cannot be negative;
h = 6
Hence he height of the banner is 6
6 and 11 and 3 and 22.
The order of the diagram may look different however, the prime factors are the same.
x^2 +9x +25 + 44/x-2
Step-by-step explanation:
75 = 5 x 3 x 5
We can solve this using a factor tree.
75
/ \
5 15
/ \
3 5
We're given a set of exterior angles for a polygon, here a quadrilateral. Exterior angles of any polygon add to 360 degrees.
46 + (12x + 37) + (12x - 2) + (20x - 29) = 360
44 x + 52 = 360
44 x = 308
x = 308/44 = 7
Check: The supplementary angles should add to 360 as well, they're the interior angles of a quadrilateral
(180-46) + (180 - (12(7) + 37)) + (180 - (12(7) - 2)) + (180 - (20(7) - 29)) = 360, good
Answer: 7
