one may note that the interval of [ -π , π ) is pretty much the whole circle in one revolution, exception π.
![\bf \textit{Pythagorean Identities} \\\\ sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta)\implies cos(\theta)=\sqrt{1-sin^2(\theta)} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ sin(x)=cos(x)\implies sin(x)=\sqrt{1-sin^2(x)} \\[1.5em] [sin(x)]^2=\left[\sqrt{1-sin^2(x)}\right]^2\implies sin^2(x) = 1-sin^2(x)\implies 2sin^2(x)=1](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7BPythagorean%20Identities%7D%20%5C%5C%5C%5C%20sin%5E2%28%5Ctheta%29%2Bcos%5E2%28%5Ctheta%29%3D1%5Cimplies%20cos%5E2%28%5Ctheta%29%3D1-sin%5E2%28%5Ctheta%29%5Cimplies%20cos%28%5Ctheta%29%3D%5Csqrt%7B1-sin%5E2%28%5Ctheta%29%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20sin%28x%29%3Dcos%28x%29%5Cimplies%20sin%28x%29%3D%5Csqrt%7B1-sin%5E2%28x%29%7D%20%5C%5C%5B1.5em%5D%20%5Bsin%28x%29%5D%5E2%3D%5Cleft%5B%5Csqrt%7B1-sin%5E2%28x%29%7D%5Cright%5D%5E2%5Cimplies%20sin%5E2%28x%29%20%3D%201-sin%5E2%28x%29%5Cimplies%202sin%5E2%28x%29%3D1)
Answer:
The interest that is obtained from that investment is $55.2
Step-by-step explanation:
If the balance at the end of eight years on an investment of $230 that has been invested at a rate of 3% is $285.20, so the principal of investment is $230 and the matured sum is $285.20.
Now, we know that Principal + Interest = Matured sum.
Hence, the interest that is obtained from that investment is $(285.2 - 230) = $55.2 (Answer)
Answer:
(-37,90)
Step-by-step explanation:
96-6/27-66
Answer:
$1032.87
Step-by-step explanation:
First we need to calculate the interest
Interest = Principal * rate * time/100
Interest = 1000 * 12 * 100/365 * 100
Interest = 12000/365
Interest = 32.87
maturity value = Principal + Interest
maturity value = 1000 + 32.87
maturity value = $1032.87
0.8x + 0.2x = 1, 0.8 being orange juice, 0.2 being water.
80 percent of one is 0.8, converted into ml, which is x1000, there is 800ml of orange juice in the can
