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kati45 [8]
3 years ago
5

John throws a rock straight down with speed 12 m/s from the top of a tower. the rock hits the ground after 2.37 s. what is the h

eight of the tower? (air resistance is negligible)
Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
3 0
12*2.37= 28.44

The tower is 28.44 meters tall.






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A square technology chip has an area of 25 square centimeters how long is each side of the chip
grigory [225]

ANSWER

Each side of the chip is 5 centimeters long.


<u>EXPLANATION</u>

The chip is in the form of a square.


The formula for finding the area of a square is

Area=l^2


We were given in the question that, the area is 25 square centimeters. This means that,


25=l^2


We take the square root of both sides to get,


\sqrt{25}=l


\Rightarrow 5=l


Hence the length of the square technology chip is 5 centimeters



5 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Ccolor%7Bred%7D%7B%5Ctt%20%7BIn%20%5C%3A%20%20%CE%94%20%5C%3A%20%20ABC%2C%20%E2%88%A0B%3D90%
makkiz [27]

Use Pythagoras theorem

Hypotenuse²=Base²+ Height ²

H²=(8)²+(6)²

H²=64+36

H²= 910

H²=10√91 cm Solution

5 0
2 years ago
Read 2 more answers
a box contains 'n' quarters and some dimes. the ratio of quarters to dimes is 1:2. write an expression for the total number of m
True [87]
The ratio 1:2 means there are twice as many dimes as there are quarters.  An expression could be n=2d, n being number of quarters, d being number of dimes.
3 0
3 years ago
There are 1,295 students attending a small university.There are 714 women enrolled. What percent of the students are women. Equa
Semenov [28]
If 1295 × p = 714, then you can rearrange the equation to find the percentage.

You have to get p on its own, so you divide 1295 on both sides of the '='.

1295 × p = 714

p = 714 ÷ 1295

p = <span>0.55135135135...

p </span>× 100 = actual percentage

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8 0
3 years ago
4. Two families went camping. The Becker family was 4 miles west of the campsite lake. The Dunn family
tresset_1 [31]

They were 1 mile away from each other.

4-3=1 mile

8 0
3 years ago
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