Answer:
x +0y+0z = 400
-x +y+0z = 150
-8x +0y +z = 250
Step-by-step explanation:
The last column is the solution
The rest of the columns are the coefficients of the variables
x +0y+0z = 400
-x +y+0z = 150
-8x +0y +z = 250
Given:
Consider the height of the rocket, in feet after x seconds of launch is

To find:
The time at which the rocket will reach its max, to the nearest 100th of a second.
Solution:
We have,

It is a quadratic polynomial with negative leading coefficient. So, it is a downward parabola.
Vertex of a downward parabola is the point of maxima.
To find the time at which the rocket will reach its max, we need to find the x-coordinate of the vertex.
If a quadratic function is
, then the vertex is

Here,
.
So,



So, x-coordinate of the vertex is 4.75.
Therefore, the rocket will reach its max at 4.75 second.
Answer:
90 degrees
Step-by-step explanation:
All trapazoids are equal to 360 degrees.
so we can make an equation 2x+x+x=360 (the other corner would also be x because its an unknown value)
to simplify, 4x=360
you divide into both sides (360/4)
you get 90
The first option
Reflect triangle UTS over the line y=2 and dilate it by a scale factor of 2 from point S