Domain: ( -infinity, infinity ) , { x|x € R }
Range: ( -infinity, infinity ) , { y|y € R }
Answer:
see explanation
Step-by-step explanation:
I will begin with part two, first.
The equation of a circle in standard form is
(x - h)² + (y - k)² = r²
where (h, k) are the coordinates of the centre and r is the radius.
Given
x² - 18x + y² - 10y = - 6
Using the method of completing the square
add ( half the coefficient of the x/ y terms )² to both sides
x² + 2(- 9)x + 81 + y² + 2(- 5)y + 25 = - 6 + 81 + 25, that is
(x - 9)² + (y - 5)² = 100 ← in standard form
with centre = (9, 5 ) and r =
= 10
Answer:
18/4
Step-by-step explanation: in order to get an equivalent ration just multiply both numerator and denominator by the same number
in this case I multiplied by 2 and got 18/4
Answer:
7x +5
Step-by-step explanation:
Mason works h hours each day during the 5-day workweek. He also works 5 hours on the weekend. Write an algebraic expression for the number of hours Mason works each week.
"h hours each day in the week"
There are 7 days, so 7 × x.
"5 hours on the weekend"
5
So, this can be written as 7x + 5.
<em>Hope I helped, have a nice day!</em>
<em> -Aadi x</em>
Answer:
Maximum area = 800 square feet.
Step-by-step explanation:
In the figure attached,
Rectangle is showing width = x ft and the side towards garage is not to be fenced.
Length of the fence has been given as 80 ft.
Therefore, length of the fence = Sum of all three sides of the rectangle to be fenced
80 = x + x + y
80 = 2x + y
y = (80 - 2x)
Now area of the rectangle A = xy
Or function that represents the area of the rectangle is,
A(x) = x(80 - 2x)
A(x) = 80x - 2x²
To find the maximum area we will take the derivative of the function with respect to x and equate it to zero.

= 80 - 4x
A'(x) = 80 - 4x = 0
4x = 80
x = 
x = 20
Therefore, for x = 20 ft area of the rectangular patio will be maximum.
A(20) = 80×(20) - 2×(20)²
= 1600 - 800
= 800 square feet
Maximum area of the patio is 800 square feet.