AB =
The midpoint os segment AB =
The midpoint is:
(1,-4)
The midpoint os segment AB =
The midpoint is:
(1,-4)
. The formula to find the surface area of a sphere is to take the radius of the sphere and square
1 answer:
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Domain is the set of numbers you can subsitute for the input (in this case x) and for it to be allowed (dividing by zero is not allowed so if you have y=6/x then x is not allowed to be zero, it can be anything else though)
ok, so from experience the x^2-4x-12 part is supposed to be all under the parenthaseeese and if so, go to part AAAAAAAAAAAAA
if it isn't and only x^2 is below the fraction, then go to BBBBBBBB
AAAAAAAAA
so the domain must be valid
one rule that we have is that you cannot divide by zero
therefor we find what numbers make the denomenator zero and don't allow them
x^2-4x-12=0
factor
(x-6)(x+2)=0
x-6=0
x=6
x+2=0
x=-2
so since -2 and 6 make the thingummy zero, we say that
domain={all real numbers except for -2 and 6}
BBBBBBBBBBBBBBB
so remember that you cannot divide by zero
therefor you have to make sure the deomenator is not equal to zero by finding those values and restricting them from the solution set
so
x^2=0
squaer root both sides
x=0
domain={all real numbers except for 0}
so if the x^2-4x-12 is under the dividing line, then the answer is domain={all real numbers except for -2 and 6}
if the x^2 only is under the dividing line then the answer is domain={all real numbers except for 0}
ok, so from experience the x^2-4x-12 part is supposed to be all under the parenthaseeese and if so, go to part AAAAAAAAAAAAA
if it isn't and only x^2 is below the fraction, then go to BBBBBBBB
AAAAAAAAA
so the domain must be valid
one rule that we have is that you cannot divide by zero
therefor we find what numbers make the denomenator zero and don't allow them
x^2-4x-12=0
factor
(x-6)(x+2)=0
x-6=0
x=6
x+2=0
x=-2
so since -2 and 6 make the thingummy zero, we say that
domain={all real numbers except for -2 and 6}
BBBBBBBBBBBBBBB
so remember that you cannot divide by zero
therefor you have to make sure the deomenator is not equal to zero by finding those values and restricting them from the solution set
so
x^2=0
squaer root both sides
x=0
domain={all real numbers except for 0}
so if the x^2-4x-12 is under the dividing line, then the answer is domain={all real numbers except for -2 and 6}
if the x^2 only is under the dividing line then the answer is domain={all real numbers except for 0}