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egoroff_w [7]
3 years ago
14

Domain of y= 6x+13/x^2-4x-12

Mathematics
1 answer:
borishaifa [10]3 years ago
5 0
Domain is the set of numbers you can subsitute for the input (in this case x) and for it to be allowed (dividing by zero is not allowed so if you have y=6/x then x is not allowed to be zero, it can be anything else though)

ok, so from experience the x^2-4x-12 part is supposed to be all under the parenthaseeese and if so, go to part AAAAAAAAAAAAA
if it isn't and only x^2 is below the fraction, then go to BBBBBBBB


AAAAAAAAA
y= \frac{6x+13}{x^{2}-4x-12}
so the domain must be valid
one rule that we have is that you cannot divide by zero
therefor we find what numbers make the denomenator zero and don't allow them
x^2-4x-12=0
factor
(x-6)(x+2)=0
x-6=0
x=6

x+2=0
x=-2

so since -2 and 6 make the thingummy zero, we say that

domain={all real numbers except for -2 and 6}




BBBBBBBBBBBBBBB
y= \frac{6x-13}{x^{2}} -4x-12

so remember that you cannot divide by zero
therefor you have to make sure the deomenator is not equal to zero by finding those values and restricting them from the solution set
so
x^2=0
squaer root both sides
x=0
domain={all real numbers except for 0}





so if the x^2-4x-12 is under the dividing line, then the answer is domain={all real numbers except for -2 and 6}

if the x^2 only is under the dividing line then the answer is domain={all real numbers except for 0}
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Answer: She started with $160.

It will take 6 weeks before she has less than half of what she originally invested.

Step-by-step explanation:

If her money is decreasing in value by 11% each week, it means that the rate at which it is decreasing is exponential.

We would apply the formula for exponential decay which is expressed as

A = P(1 - r)^t

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r represents rate of depreciation.

From the information given,

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t = 1

Therefore

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For her to have half of what she invested originally, then

80 = 160(0.89)^t

80/160 = (0.89)^t

0.5 = (0.89)^t

Taking log of both sides to base 10

Log 0.5 = log0.89^t = tlog0.89

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t = - 0.3010/- 0.051

t = 5.9

Approximately 6 weeks

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