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AlekseyPX
3 years ago
15

Jeanine is twice as old as her brother Marc. If the sum of their ages is 24, how old is Jeanine

Mathematics
2 answers:
Vesna [10]3 years ago
5 0
Her brother is 8: 8 x 2 is 16, and 16 + 8= 24.
docker41 [41]3 years ago
5 0
First make an equation system for the problem
An equation for "<span>Jeanine is twice as old as her brother Marc" is
</span>⇒ j = 2m
An equation for "<span>the sum of their ages is 24" is
</span>⇒ j + m = 24
<span>
Second solve the equations with subtitution method.
Subtitute j with 2m in the second equation
j + m = 24
2m + m = 24
3m = 24
m = 24/3
 m = 8
Marc is 8 years old

Find Jeanine's age by subtitute m with 8 in the first equation
j = 2m
j = 2(8)
j = 16

Jeanine is 16 years old
</span>
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find the smaller of 2 consecutive integers,x, if the sum of the smaller and 6 times the larger is -29
AnnyKZ [126]

Answer:-  The smaller integer is -5.


Explanation:-

Let the first consecutive integer be x and the second consecutive integer be x+1.

According to the given question:-

x+6(x+1)= -29

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3 0
3 years ago
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Anuta_ua [19.1K]
I get the answer being the same y= -1/2x +

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I used
m=y2-y1/x2-x1
M=-3-2/6-4
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(-4,2)
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I did the same for second point
And got "0" for b


So my answer is get
Y=-1/2x


Unless someone else gets something else different.

I hope somewhat helps
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2 years ago
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valentinak56 [21]

Answer:

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Step-by-step explanation:

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5 0
3 years ago
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