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AlekseyPX
3 years ago
15

Jeanine is twice as old as her brother Marc. If the sum of their ages is 24, how old is Jeanine

Mathematics
2 answers:
Vesna [10]3 years ago
5 0
Her brother is 8: 8 x 2 is 16, and 16 + 8= 24.
docker41 [41]3 years ago
5 0
First make an equation system for the problem
An equation for "<span>Jeanine is twice as old as her brother Marc" is
</span>⇒ j = 2m
An equation for "<span>the sum of their ages is 24" is
</span>⇒ j + m = 24
<span>
Second solve the equations with subtitution method.
Subtitute j with 2m in the second equation
j + m = 24
2m + m = 24
3m = 24
m = 24/3
 m = 8
Marc is 8 years old

Find Jeanine's age by subtitute m with 8 in the first equation
j = 2m
j = 2(8)
j = 16

Jeanine is 16 years old
</span>
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Option A

If  f(x) = 2x^2 + 1 and g(x) = x^2 - 7 then (f - g)(x) = x^2 + 8

<em><u>Solution:</u></em>

Given that f(x) = 2x^2 + 1 and g(x) = x^2 - 7

To find: (f - g)(x)

We know that,

(f – g)(x) = f (x) - g(x)

Let us substitute the given values of f(x) and g(x) in above formula,

(f - g)(x) = 2x^2 + 1 - (x^2 - 7)

For solving the brackets in above expression,

There are two simple rules to remember:

When you multiply a negative number by a positive number then the product is always negative.

When you multiply two negative numbers or two positive numbers then the product is always positive.

So the expression becomes,

(f - g)(x) = 2x^2 + 1 -x^2 + 7

Combining the like terms,

(f - g)(x) = 2x^2 - x^2 + 1 + 7\\\\(f - g)(x) = x^2 + 8

Thus option A is correct

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3 years ago
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