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3 years ago

Who got the answer to this ? (4x^2+6+7)-(-8x^2-2x+6)

Mathematics

1 answer:

Andru [333]3 years ago

7 0

Answer:

12x^2+2x+7

Step-by-step explanation:

Distribute the Negative Sign:

=4x^2+6+7+−1(−8x^2−2x+6)

=4x^2+6+7+−1(−8x^2)+−1(−2x)+(−1)(6)

=4x^2+6+7+8x^2+2x+−6

Combine Like Terms:

=4x^2+6+7+8x^2+2x+−6

=(4x^2+8x^2)+(2x)+(6+7+−6)

=12x^2+2x+7

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Arisa [49]

<h2>Answer: A trapezoid with bases of 6 mm and 14 mm and a height of 8 mm </h2>

The parallelogram in the figure has an area of $80mm^{2}$ , according to the following formula, which works for all rectangles and parallelograms:

$A_{parallelogram}=(b)(h)$ (1)

Where $b$ is the base and $h$ is the height

The<u> area of a triangle</u> is given by the following formula:

$A_{triangle}=\frac{1}{2}(b)(h)$ (2)

So, for option A:

$A_{triangle}=\frac{1}{2}(4mm)(20mm)=40mm^{2} \neq 80mm^{2}$

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$A_{trapezoid}=\frac{1}{2}(b_{1}+ b_{2})(h)$ (3)

For option B:

$A_{trapezoid}=\frac{1}{2}(15mm+25mm)(2 mm)=40mm^{2} \neq 80mm^{2}$

For option C:

$A_{trapezoid}=\frac{1}{2}(6mm+14mm)(8 mm)=80mm^{2}$ >>>>This is the correct option!

For option D:

$A_{rectangle}=(30mm)(8mm)=240mm^{2} \neq 80mm^{2}$

<h2>Therefore the correct option is C</h2>

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2 years ago

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3 years ago

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Combine like terms.

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3 years ago