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sergiy2304 [10]
3 years ago
5

Who got the answer to this ? (4x^2+6+7)-(-8x^2-2x+6)

Mathematics
1 answer:
Andru [333]3 years ago
7 0

Answer:

12x^2+2x+7

Step-by-step explanation:

Distribute the Negative Sign:

=4x^2+6+7+−1(−8x^2−2x+6)

=4x^2+6+7+−1(−8x^2)+−1(−2x)+(−1)(6)

=4x^2+6+7+8x^2+2x+−6

Combine Like Terms:

=4x^2+6+7+8x^2+2x+−6

=(4x^2+8x^2)+(2x)+(6+7+−6)

=12x^2+2x+7

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Y=-7x-15

The formula to write the equation is

Y=mx+b

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8 0
3 years ago
Please help thank you!
Arte-miy333 [17]

Answer:

  • golf: $10
  • batting: $2.50

Step-by-step explanation:

We can write two equations in the two unknowns using the given relations. Let g and b represent the costs of a round of golf and a turn in the batting cage, respectively.

  5g +4b = 60 . . . . . Sylvester's expense

  3g +6b = 45 . . . . . Lin's expense

Dividing the second equation by 3 gives ...

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Substituting into the first equation, we have ...

  5g +2(2b) = 60

  5g +2(15 -g) = 60 . . . . . substitute for 2b

  3g = 30 . . . . . . . . . subtract 30, collect terms

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Mini golf costs $10 per round; batting cages cost $2.50 per turn.

7 0
2 years ago
At a specific point on a highway, vehicles arrive according to a Poisson process. Vehicles are counted in 12 second intervals, a
morpeh [17]

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Step-by-step explanation:

Since we have given that

P(n) = \dfrac{15}{120}=0.125

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P(n)=\dfrac{(\lambda t)^n\times e^{-\lambda t}}{n!}\\\\P(n=0)=0.125=\dfrac{(\lambda \times 14)^0\times e^{-14\lambda}}{0!}\\\\0.125=e^{-14\lambda}\\\\\ln 0.125=-14\lambda\\\\-2.079=-14\lambda\\\\\lambda=\dfrac{2.079}{14}\\\\0.1485=\lambda

So, for exactly one car would be

P(n=1) is given by

=\dfrac{(0.1485\times 14)^1\times e^{-0.1485\times 14}}{1!}\\\\=0.2599

Hence, our required probability is 0.2599.

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Number of these intervals in which exactly one car arrives is given by

0.2599\times 18=4.6798

We will find the traffic flow q such that

P(0)=e^{\frac{-qt}{3600}}\\\\0.125=e^{\frac{-18q}{3600}}\\\\0.125=e^{-0.005q}\\\\\ln 0.125=-0.005q\\\\-2.079=-0.005q\\\\q=\dfrac{-2.079}{-0.005}=415.88\ veh/hr

b. Estimate the percentage of time headways that will be 14 seconds or greater.

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7 0
3 years ago
P(x) ---&gt;p(x+6)+3 ? what would the graph look like?
Setler79 [48]
<span>given that P(x) --->p(x+6)+3
</span>
∴ x will become x+6
and P(x+6) will become P(x+6)+3
<span />
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OR by another words, we need to make axis translations from (0,0) to (-6,3)

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