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xz_007 [3.2K]
3 years ago
6

A moving trailer with a speed of 70km/h slows down its speed by 15% within 30 seconds. calculate the declaration of the trailer.

Mathematics
1 answer:
antoniya [11.8K]3 years ago
7 0

Answer:

declaration = - 0.55 m/s²

Step-by-step explanation:

The declaration is a negative accelaration.

Therefore:

a = \frac{v-u}{t}

a      = ?

v      = 70 of 15% = 10.5 km/h to m/s = 2.9 m/s

u = 70 km/h to m/s = 19.4 m/s

t = 30 seconds

a = \frac{2.9-19.4}{30}\\

a = - 0.55 m/s²

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the angle of elevation of the top of a building from a point 80 ft away from the building on level ground is 70° determine the b
MA_775_DIABLO [31]
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Then the height of the building is the 2nd shortest side.

The tangent function is the appropriate one to use here:
                       opp          h
tan 70 deg = -------- = ----------
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Since tan 70 deg  = 2.75,          2.75 = -------
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6 0
4 years ago
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stiv31 [10]

That would be written as:

z^{2} = 1


And the step-by-step equation would be:

z^{2} = 1 → we take the 2 to the right side of the equation and do the IO*

z = \sqrt{1} →we solve for \sqrt{1}

z = 1 → final answer


*Ps - IO is not an existing term and stands for inverse operation. In this case, because when we take to 2 to the right side of the equation (the 2 is a power) it'll have to turn into a square root (because exponents and roots are inverse operations)



Hope it helped,



BioTeacher101

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defon
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