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NISA [10]
3 years ago
6

How do you simplify the expression: k^13 · k^17 over k^5 · k^11

Mathematics
2 answers:
AVprozaik [17]3 years ago
7 0

Answer:

k^14

Step-by-step explanation:

marshall27 [118]3 years ago
5 0
Since they have the same base all you would do is add the exponents, which makes the top one k^30, and the same with the bottom which makes that one k^16, then you subtract the exponent from where it’s higher so i’d be k^30-k^16 which makes it k^14 over 1
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