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neonofarm [45]
4 years ago
14

I’m really stuck on this problem. please explain the work! 4y-70=12y+2 thanks :)

Mathematics
2 answers:
Trava [24]4 years ago
5 0
You’re answer for this problem will be -9
JulijaS [17]4 years ago
5 0

Answer:

y = -9

Step-by-step explanation:

4y - 70 = 12y + 2

Add 70 to both sides

4y - 70 + 70 = 12y + 2 + 70

simplify

4y = 12y + 72

subtact 12y from both sides

4y - 12y = 12y + 72 - 12y

simplify

-8y = 72

divide both sides by -8

-8y divided by -8 = 72 divided by -8

solve

y = -9

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The length breadth and height of a sectangular box are 24 cm, 6 cm and 2cm respectevely. Find the area of largest surface of box
slamgirl [31]

Answer:

408cmx^{2}

Step-by-step explanation:

A=2(wl+hl+hw)=2·(2·6+24·6+24·2)= 408cm²

6 0
2 years ago
8-35. Use your knowledge of polygons to answer the questions below, if possible.
Nataliya [291]

Answer:

(a)I. 13 Sides II. 7 Sides

(b) 4 Sides, Square

(c)x=52 degrees

(d)x=107 degrees

(e)1620 degrees

Step-by-step explanation:

(a)The Sum of the Interior angle of polygon with n sides is derived using the formula: (n-2)180.

I. If the Interior angle is 1980^0

Then:

(n-2)180^0=1980^0\\$Divide both sides by 180^0 $ to isolate n$\\n-2=11\\$Add 2 to both sides of the equation\\n-2+2=11+2\\n=13

The polygon has <u>13 sides.</u>

II. If the Interior angle is 900^0

Then:

(n-2)180^0=900^0\\$Divide both sides by 180^0 $ to isolate n$\\n-2=5\\$Add 2 to both sides of the equation\\n-2+2=5+2\\n=7

The polygon has <u>7 sides.</u>

(b)The sum of the exterior angle of a polygon is 360 degrees,

Each exterior angle of a n-sided regular polygon is: \frac{360^0}{n}

If the exterior angle of a regular polygon is 90°

Then:

90\°=\frac{360^0}{n}\\ 90n=360\\n=4

The regular polygon has 4 sides and it is called a <u>Square.</u>

<u>(c)</u>The Sum of the Interior angle of polygon with n sides is derived using the formula: (n-2)180.

Each Interior angle of a regular n-sided polygon is:  \frac{(n-2)180^0}{n}

For a pentagon, n=5

Then:

\frac{(5-2)180^0}{5}=2x+4\\108=2x+4\\108-4=2x\\104=2x\\x=52^0

(d)The <u>sum of the exterior angle of a polygon is 360 degrees.</u>

If four of the exterior angles of a pentagon are 57, 74, 56, and 66.

Let the fifth angle=x

Then:

57+74+56+66+x=360^0\\253+x=360\\x=107^0

(e)The Sum of the Interior angle of polygon with n sides is derived using the formula: (n-2)180.

In an 11-gon., n=11

Therefore, the sum of the interior angle=(11-2)180=1620^0

The sum of the interior angle <u>does not change either in a regular or irregular polygon.</u>

3 0
3 years ago
Please help. Sine and Cosine rules
kodGreya [7K]

Answer:

a=41.8 BC=2.8

Step-by-step explanation:

sin30/6=sinx/8

8*sin30=6sinx

4=6sinx

sin^-1(4/6)

angle a

cosine rule

bc^2=3^2 +5^2-2(3)(5)*cos30

BC^2=\sqrt8.019237886\\

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2.8

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3 years ago
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andreyandreev [35.5K]

Answer:

f - 1 (x)  = - x6 - 76

Step-by-step explanation:

Since g(f(x))=x g ( f ( x ) ) = x , f−1(x)=−x6−76 f - 1 ( x ) = - x 6 - 7 6 is the inverse of f(x)=−6x−7 f ( x ) = - 6 x - 7 .

7 0
2 years ago
How can I solve these problems​
Anuta_ua [19.1K]
Here’s the first few and you can do the rest with the same principles. If you need more help with the last ones then let me know

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3 years ago
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