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NARA [144]
3 years ago
14

A rectangle with an area of 4/7 meters squared is dilated by a factor of 7. What is the area of the dilated rectangle?

Mathematics
1 answer:
nikklg [1K]3 years ago
7 0

Answer:

49

Step-by-step explanation:

Every time you multiply both sides of a rectangle by a number x, its area if multiplied by x^{2}.

In our example:

Area of a rectangle = width . length

width = 4

length   = 7

A_{1} = 4 . 7 = 28

When you multiply both sides by 7:

width = 4 . 7 = 28

length = 7 . 7 = 49

A_{2}  = 28 . 49

A_{2}  = 1372

A_{2}  / A_{1} = 1372 / 28 = 49 = (7)^{2}

Both sides multiplied by 7 => Area multiplied by 7^{2}

Got it?

;-)

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Answer:

The 3 odd, consecutive numbers are 25, 27, and 29.

Step-by-step explanation:

When you add these 3 numbers you will get 81.

25 + 27 = 52

52 + 29 = 81

Therefore, 25 + 27 + 29 = 81

Hope this helps!!

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Find the equation of the line that is parallel to the given line and passes through the given point
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Answer:

\huge\boxed{y=-\dfrac{1}{4}x-1\to x+4y=-4}

Step-by-step explanation:

\text{Let}\ k:y=m_1x+b_1;\ l:y=m_2x+b_2\\\\l\ ||\ k\iff m_1=m_2\\\\l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}\\==========================\\\\\text{We have}\ x+4y=-6.\\\text{Convert to the slope-intercept form:}\\\\x+4y=-6\qquad\text{subtract}\ x\ \text{from both sides}\\\\4y=-x-6\qquad\text{divide both sides by 4}\\\\y=\dfrac{-x}{4}-\dfrac{6}{4}\\\\y=-\dfrac{1}{4}x-\dfrac{3}{2}\to m_1=-\dfrac{1}{4}

\text{Lines are to be parallel. Therefore}\ m_2=-\dfrac{1}{4}.\\\\\text{We initially have the form equation}\ y=-\dfrac{1}{4}x+b.\\\\\text{The line passes through the point}\ (9,\ -3).\\\\\text{Substitute the coordinates of the point to the equation of a line:}\\\\x=9,\ y=-3\\\\-3=-\dfrac{1}{4}(9)+b\\\\-3=-\dfrac{9}{4}+b\qquad\text{add}\ \dfrac{9}{4}\ \text{to both sides}\\\\-\dfrac{12}{4}+\dfrac{9}{4}=b\to b=-\dfrac{3}{4}

\text{Lines are to be parallel. Therefore}\ m_2=-\dfrac{1}{4}.\\\\\text{We initially have the form equation}\ y=-\dfrac{1}{4}x+b.\\\\\text{The line passes through the point}\ (8,\ -3).\\\\\text{Substitute the coordinates of the point to the equation of a line:}

x=8,\ y=-3\\\\-3=-\dfrac{1}{4}(8)+b\\\\-3=-2+b\qquad\text{add 2 to both sides}\\\\-1=b\to b=-1

\text{Therefore the equation is:}\ y=-\dfrac{1}{4}x-1.\\\\\text{Convert to the standard form}\ Ax+By=C:\\\\y=-\dfrac{1}{4}x-1\qquad\text{multiply both sides by 4}\\\\4y=-x-4\qquad\text{add}\ x\ \text{to both sides}\\\\x+4y=-4

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4 years ago
Verify <br>cos^4x-sin^4x=cos2x
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<span>cos^4x-sin^4x =( cos^2x + sin^2x )( cos^2x - sin^2x) = 1* cos2x = co2x.</span>
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