Answer:
The value is c = 21.1445.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
The weight distribution of parcels sent in a certain manner is normal with mean value 12lb and standard deviation 3.5 lb.
This means that 
What value of c is such that 99% of all parcels are at least 1 lb under the surcharge weight?
This 1 added to the value of X for the 99th percentile, which is X when Z has a p-value of 0.99, so X when Z = 2.327.




1 + 20.1445 = 21.1445
The value is c = 21.1445.
Answer:
800
Step-by-step explanation:
Given: The selling price of bed is 2400.
Discount offered is 25%
Lets assume the cost of bed be "x"
Discount offered on the cost price of bed= 
∴ Discount offered on the cost price of bed= 0.25x
We know the selling price of bed after discount provided.
Finding the cost price of the bed.
⇒ 
⇒ 
cross multiplying both side.
∴ 
∴ Cost price of the bed is 3200.
We know selling price of the bed is 2400.
Now, finding the saving.
Saving on the price of bed= Cost price- selling price
Saving= 
Hence, saving on the purchase of the bed is 800.
Yes it can be a triangule
Answer:
G(7)= 4
Step-by-step explanation:
When looking at the graph, you can see that at x=7, y= 4 :)