Question

Complete the equation of the line through (-9,7) & (-6,-3)

Answer 1

Answer:

$y=-\frac{10}{3}x-23$

Step-by-step explanation:

we have the points

(-9,7) and (-6,-3)

step 1

Find the slope

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

substitute the values

$m=\frac{-3-7}{-6+9}$

$m=-\frac{10}{3}$

step 2

Find the equation in point slope form

$y-y1=m(x-x1)$

we have

$m=-\frac{10}{3}$

$(x1,y1)=(-6,-3)$

substitute

$y+3=-\frac{10}{3}(x+6)$  ---> equation in point slope form

step 3

Find the equation of the line in slope intercept form

$y=mx+b$

we have

$y+3=-\frac{10}{3}(x+6)$

Isolate the variable y

Distribute right side

$y+3=-\frac{10}{3}x-20$

subtract 3 both sides

$y=-\frac{10}{3}x-20-3$

$y=-\frac{10}{3}x-23$