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OleMash [197]
4 years ago
15

Alex purchased a new car for $28,000. The car's value depreciates 7.25% each year. What will be the value of the car 5 years aft

er it is purchased? Round your answer to the nearest dollar.
Mathematics
2 answers:
Vlad1618 [11]4 years ago
7 0
7.25/100 = 0.0725 => 0.0725 × 28,000 = 2,030$
2030 × 5 = 10,150$ => 28,000 + 10,150 = 38,150$
Margarita [4]4 years ago
7 0
28,000x0.0725=2030 per year, so 2030x5= 10,150

then, 28,000-10150= 17,850
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Licemer1 [7]
The correct answer is -5
8 0
3 years ago
Use the list below to find the upper quartile. 27, 5, 11, 13, 10, 8, 14, 18, 7
Alinara [238K]

Find the  median first. The middle of all the numbers.

5, 7, 8, 10, 11, 13, 14, 18, 27

11 is the median.

Then find the median of the upper quartile.

The upper quartile consists of numbers...

5, 7, 8, 10

Since it is an even set of numbers add the two in the middle and divided by two. So 7 plus 8=  15/2.

7.5 is your upper quartile.

4 0
3 years ago
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Multiply: 2.7 × (–3) × (–1.2). A. –9.72 B. –10.8 C. 10.8 D. 9.72
Vikentia [17]

Answer:  \text{ D) } 9.72

Step-by-step explanation:

Here the give expression is,

2.7 \times(-3)\times (-1.2)

We can write,

2.7 \times(-3)\times (-1.2) = 2.7 \times 3.6  ( because -a\times -b = ab)

2.7 \times(-3)\times (-1.2) = 9.72

⇒ Option D is correct.

6 0
3 years ago
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Clare made a smoothie with 1 cup of yogurt, 3 tablespoons of peanut butter, 2 teaspoons of chocolate syrup, and 2 cups of crushe
Ugo [173]

Answer: it was probably more chocolaty because he added 5 teaspoons instead of 4 which is 2 doubled

Step-by-step explanation:

4 0
3 years ago
Mrs. Gilbert is interested in determining how many students spend 4 or more hours doing homework each week. She asks every stude
docker41 [41]

Answer:

C. Biased, because she only asked students on honor roll.

Step-by-step explanation:

Since Mrs. Gilbert's goal was to find how many students that spent >4 hours and not how many students that earned Honor Roll that spent >4 hours, the data is biased. Choose C.

4 0
3 years ago
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